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mote1985 [20]

3 years ago

"7 \times 3 \times 3 = " align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Eduardwww [97]3 years ago

8 0

63 is your answer :)

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Can someone help me. I don't get this

Gala2k [10]

Last option — a decimal that terminates after three decimal places

Hope this helps good luck u can do thisss :)

4 0

3 years ago

Find the angle between vector u=2i+sqrt(11)j and v=-3i-2j to the nearest degree

const2013 [10]

Answer: Last option 155°

Step-by-step explanation:

We have the components of the vectors u and v.

Then, to find the angle between them, perform the following steps:

1) Calculate the scalar product u * v

If $u = 2i + \sqrt{11}j$ and $v = -3i-2j$

Then, the product scalar u * v is:

$u * v = (2)(-3) + (\sqrt{11})(-2)$

$u * v = -6-2\sqrt{11}$

$u * v = -12.633$

2) Calculation of the magnitude of both vectors.

$| u | = \sqrt{(2) ^ 2 + (\sqrt{11})^2}\\\\| u | = \sqrt{4+11}\\\\| u | = \sqrt{15}$

$| v | = \sqrt{(- 3) ^ 2 + (- 2) ^ 2}\\\\| v | = \sqrt{9 +4}\\\\| v | = \sqrt{13}$

3) Now that you know the product point between the two vectors and the magnitude of each, then use the following formula to find an angle

$u * v = | u || v |cos(\alpha)$

$-12.633 = \sqrt{15}\sqrt{13}*cos(\alpha)\\\\cos(\alpha) = \frac{-12.633}{\sqrt{15}\sqrt{13}}\\\\arcos(\frac{-12.633}{\sqrt{15}\sqrt{13}}) = \alpha\\\\\alpha =155\°$

7 0

4 years ago

Hurry I need help help

insens350 [35]

Step-by-step explanation:

C. This system is consistent. It has one solution.

particularly in algebra, a linear or nonlinear system of equations is called consistent

6 0

3 years ago

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Answer the following questions.

ivolga24 [154]

Answer: 864,000‬

Step-by-step explanation:

and that's if it's multiplication

5 0

3 years ago

My sister needs help with this please someone help her

olga2289 [7]

Answer:

1/5 ; 1.64

Step-by-step explanation:

Cara used 1.64 pints of blue paint or 1/5 of 8.2.

3 0

3 years ago

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