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mote1985 [20]
3 years ago
8

"7 \times 3 \times 3 = " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Eduardwww [97]3 years ago
8 0

63 is your answer :)

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If the area of a right-angled triangle is 47 56 cm and its height is 11.6 cm. finds its base.​
Wewaii [24]

Answer:

820          

Step-by-step explanation:

Hi so if your area is 4756, the base would be 820

8 0
3 years ago
Could I please have help (3m+5)-(6+5m)
9966 [12]

Answer:

-2m -1

Step-by-step explanation:

(3m+5)-(6+5m)

Distribute the minus sign

(3m+5)-6-5m

Combine like terms

3m -5m +5 -6

-2m -1

5 0
3 years ago
PLEASE ANSWER ASAP Find the slope of the line
miskamm [114]

Answer:

4

Step-by-step explanation:

Slope is \frac{rise}{run}. Or, in other words the distance it travels in the y direction divided by the distance it travels in the x direction. Each time the y variable increments +4 and the x variable increments +1. Which means the line rises 4 units every time it runs 1 unit.

Slope=\frac{rise}{run}=\frac{4}{1}=4

3 0
3 years ago
I'm too lazy to do the work by myself anyway, someone please help me thank you <3 !!
In-s [12.5K]

Answer:

98

Step-by-step explanation:

10-3=7

7x7=49

49 x2 = 98

Have a good day! uwu

7 0
3 years ago
Judy’s brother Sam has a collection of 96 comic books what are the 10 where is Sam could divide his comic books into equal group
sweet-ann [11.9K]

We have been given that Judy’s brother Sam has a collection of 96 comic books. We have been asked to find the 10 ways Sam could divide his comic books into equal groups.

This can be done as follows:

96 can be written as 2\times 48=48\times 2=96. Thus, we can either have 2 groups of 48 comics or 48 groups of 2 comics. As we can see we have 2 ways to divide the comic books in equal groups.

Likewise, 96 can also be written as 3\times 32=32\times 3=96. Here, we can similarly see that we can either have 3 groups of 32 comics or 32 groups of 3 comics. As we can again see we have 2 more ways to divide the comic books in equal groups, taking the total number of ways to 4.

Continuing in this manner we will see that we can have 4 groups of 24 or 24 groups of 4, 6 groups of 16 or 16 groups of 6 and lastly 12 groups of 8 or 8 groups of 12 comic books, thus taking the count to a <u>total of 10 ways</u> in which Sam can divide his comic books into equal groups.

Our question has been answered.

5 0
3 years ago
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