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Oksi-84 [34.3K]
3 years ago
5

The slope and y intercept

Mathematics
1 answer:
Fudgin [204]3 years ago
5 0

Answer:

the y intercept is 5 because the line passes through 5 on the y axis. Now to find the slope, pick two points where the line hits directly on the corner of the grid squares. pIck 2 of those and count the squares up till you are lined up with your other point then count over and get another number. Put the number going up over the number going down like x/y and you'll have your answer. ( simplify it if you can.(-2,3) and (0,5) are a good place to start. The answer should be 2/3. Hope this helped and God bless!

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Question 15 (5 points)<br> Find the angle between u = &lt;7, -2&gt; and v= (-1,2&gt;.
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Answer:

Approximately 2.3127 radians, which is approximately 132.51^{\circ}.

Step-by-step explanation:

Dot product between the two vectors:

\begin{aligned}& u\cdot v \\ =\; & 7 \times (-1) + (-2) \times 2 \\ =\; & (-11) \end{aligned}.

Magnitude of the two vectors:

\begin{aligned} \| u \| &= \sqrt{{7}^{2} + {(-2)}^{2}} \\ &= \sqrt{53} \end{aligned}.

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Let \theta denote the angle between these two vectors. By the property of dot products:

\begin{aligned} \cos(\theta) &= \frac{u \cdot v}{\|u\| \, \| v \|} \\ &= \frac{(-11)}{(\sqrt{53})\, (\sqrt{5})} \\ &= \frac{(-11)}{\sqrt{265}}\end{aligned}.

Apply the inverse cosine function {\rm arccos} to find the value of this angle:

\begin{aligned} \theta &= \arccos\left(\frac{u \cdot v}{\| u \| \, \| v \|}\right) \\ &= \arccos\left(\frac{(-11)}{\sqrt{265}}\right) \\ & \approx \text{$2.3127$ radians} \\ &= 2.3127 \times \frac{180^{\circ}}{\pi} \\ &\approx 132.51^{\circ}\end{aligned}.

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Step-by-step explanation:

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