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Oksi-84 [34.3K]
3 years ago
5

The slope and y intercept

Mathematics
1 answer:
Fudgin [204]3 years ago
5 0

Answer:

the y intercept is 5 because the line passes through 5 on the y axis. Now to find the slope, pick two points where the line hits directly on the corner of the grid squares. pIck 2 of those and count the squares up till you are lined up with your other point then count over and get another number. Put the number going up over the number going down like x/y and you'll have your answer. ( simplify it if you can.(-2,3) and (0,5) are a good place to start. The answer should be 2/3. Hope this helped and God bless!

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Step-by-step explanation:

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Answer:

P-value is less than 0.999995 .

Step-by-step explanation:

We are given that a driver's education course compared 1,500 students who had not taken the course with 1,850 students who had.

Null Hypothesis, H_0 : p_1 = p_2 {means students who took the driver's education course and those who didn't took have same chances to pass the written driver's exam the first time}

Alternate Hypothesis, H_1 : p_1 > p_2 {means students who took the driver's education course were more likely to pass the written driver's exam the first time}

The test statistics used here will be two sample Binomial statistics i.e.;

                             \frac{(\hat p_1 - \hat p_2)-(p_1 - p_2)}{\sqrt{\frac{\hat p_1(1- \hat p_1)}{n_1} + \frac{\hat p_2(1- \hat p_2)}{n_2} } } ~ N(0,1)

Here, \hat p_1 = No. of students passed the exam ÷ No.of Students that had taken the course

 \hat p_1  = \frac{1150}{1850}            Similarly,  \hat p_2 = \frac{1440}{1500}          n_1 = 1,850       n_2 = 1,500

  Test Statistics = \frac{(\frac{1150}{1850} -\frac{1440}{1500})-0}{\sqrt{\frac{\frac{1150}{1850}(1- \frac{1150}{1850})}{1850} + \frac{\frac{1440}{1500}(1- \frac{1440}{1500})}{1500} } } = -27.38

P-value is given by, P(Z > -27.38) = 1 - P(Z > 27.38)

Now, in z table the highest critical value given is 4.4172 which corresponds to the probability value of 0.0005%. Since our test statistics is way higher than this so we can only say that the p-value for an appropriate hypothesis test is less than 0.999995 .

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