Answer:
2.66 g of Fe, can be obtained from the reaction
Explanation:
Let's think the reaction:
2Fe₂O₃ + 6CO → 4Fe + 6CO₂
Ratio is 2:4, so If i have x moles of iron (III) oxide, I will produce the double of moles of Fe.
Mass / Molar mass = Mol
3.80 g / 159.7 g/m = 0.0237 moles
0.0237 moles . 2 = 0.0475 moles
Molar mass Fe = 55.85 g/m
Mol . Molar mass = Mass → 0.0475 m . 55.85 g/m = 2.66 grams
Explanation:
Do you mean differences among various substances eg: H2O vs CO2? IMFs determine boiling and melting points by deciding how strongly molecules want to hold on to each other. The strength of IMFs depend on the type of IMFs, eg: dipole-dipole, ion-dipole, induced dipole (London dispersion), etc. Weak IMFs= low boiling point. IMFs also determine many other properties including vapor pressure, etc.
Answer : If an increase in temperature accompanies a reaction, energy is released. Explanation :In thermodynamics, the reaction is considered as a system and the medium in which the reaction occurs which is usually an aqueous medium is considered as its surrounding. When the heat flows from the system to its surrounding, it increases the temperature of surrounding medium because the heat released by the system is absorbed by its surrounding. This is known as exothermic reaction. An exothermic reaction is always accompanied by energy release. On the other hand, when the heat flows from the surrounding towards system, it decreases the temperature of the surrounding medium. This is known as endothermic reaction. From the above discussion we can say that If an increase in temperature accompanies a reaction, energy is released.
Good luck ;)
Answer:
True! Under most conditions, they are usually the same.
This is because to balance out the negativity or positivity of an atom, the opposite joins in.
Hope this helps.
Answer:
144 g
Explanation:
Use the mole ratio of 4 mol CO2 for every 9 mol O2 to convert from mol O2 to mol CO2. Then use the molar mass of CO2 to convert from mol of CO2 to grams of CO2.
7.34 mol O2 • (4 mol CO2 / 9 mol O2) • (44.01 g CO2 / 1 mol CO2) = 144 g CO2
