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3 years ago

6

Design a visual or 3-D model to represent how the positioning of multiple objects in a system can influence the potential energy

of a system.
Science help, please!

1 answer:

s2008m [1.1K]3 years ago

3 0

Answer:

hold on ur mum came over

Explanation:

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The reaction below was carried out in an acidic solution l-+10-3--->l2 Which statement is true about this equation? Although

forsale [732]

Answer:

be cool

Explanation:

there has to be a little math done in order to get ir

7 0

3 years ago

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The final volume of buffer solution must be 100.00 mL and the final concentration of the weak acid must be 0.100 M. Based on thi

Grace [21]

Answer:

0.387 g

Explanation:

pH of the buffer = 1

V = Volume of solution = 100 mL

[HA] = Molarity of HA = 0.1 M

$K_a$ = Acid dissociation constant = $1.2\times 10^{-2}$

(assuming base as $Na_2SO_410H_2O$ )

Molar mass of base = 322.2 g/mol

pKa is given by

$pK_a=-\log K_a\\\Rightarrow pKa=-\log(1.2\times 10^{-2})\\\Rightarrow pK_a=1.92$

From the Henderson-Hasselbalch equation we get

$pH=pK_a+\log\dfrac{[A^-]}{[HA]}\\\Rightarrow pH-pK_a=\log\dfrac{[A^-]}{[HA]}\\\Rightarrow 10^{pH-pK_a}=\dfrac{[A^-]}{[HA]}\\\Rightarrow [A^-]=10^{pH-pK_a}[HA]\\\Rightarrow [A^-]=10^{1-1.92}\times0.1\\\Rightarrow [A^-]=0.01202\ \text{M}$

Moles of base

$0.01202\times100\times\dfrac{1}{10^3}=0.001202\ \text{moles}$

Mass of base is given by

$0.001202\times 322.2=0.387\ \text{g}$

The required mass of the base is 0.387 g.

5 0

3 years ago

6.<br> What is the acceleration of a 24 kg mass pushed by a 6 N force?<br> I jus need number 6

Setler79 [48]

The acceleration : 0.25 m/s²

<h3>Further explanation</h3>

Given

mass = m = 24 kg

Force = F = 6 N

Required

The acceleration

Solution

Newtons' second law :

Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object

ΣF = m x a

$\large {\boxed {\bold {a = \frac {\sum F} {m}}}$

Input the value :

6 N = 24 kg x a

a = 6 : 24

a = 0.25 m/s²

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3 years ago

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Calculate the number of atoms in a 1.94 x 10^3 g sample of calcium

34kurt

$n = \frac{m}{M}$

$n = \frac{1.94*10^3}{40.08}$

$n = 48.40 mol$

Then,

$N = n*Na$
$N = 48.40*6.02*10^{23}$
$N= 2.94*10^{25}$ atoms

Hope this helps !

Photon

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3 years ago

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What happens when light rays pass through a concave lens?

valina [46]

Answer:

b)parallel light rays pass through the lens and are

refracted outward.

Hope this helps.

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3 years ago

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