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hammer [34]
3 years ago
15

How do intermolecular forces help explain differences in phase changes (boiling point, melting point)

Chemistry
1 answer:
Ivahew [28]3 years ago
3 0
Do you mean differences among various substances eg: H2O vs CO2? IMFs determine boiling and melting points by deciding how strongly molecules want to hold on to each other. The strength of IMFs depend on the type of IMFs, eg: dipole-dipole, ion-dipole, induced dipole (London dispersion), etc. Weak IMFs= low boiling point. IMFs also determine many other properties including vapor pressure, etc.
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Solve the equation for x.4+2(x-4)=-7(x+7)​
OverLord2011 [107]

Answer:

x=-5

Explanation:

we have

4+2(x-4)=-7(x+7)

Solve for x

That means----> Isolate the variable x

Applying the distributive property both sides

4+2(x)+2(-4)=-7(x)-7(7)

Remember that

(+1)(-1)=-1

4+2x-8=-7x-49

Combine like terms left side

2x-4=-7x-49

Adds 7x both sides

2x-4+7x=-7x-49+7x

9x-4=-49

Adds 4 both sides

9x-4+4=-49+4

9x=-45

Divide by 9 both sides

x=-5

4 0
3 years ago
Use VSEPR theory to predict the bond angles in a molecule of methane (CH4), which is a covalently bonded molecule.
coldgirl [10]

Answer:

109.5 Degrees

Explanation:

Because CH4 is sp4 hybridized (Carbon is bonded to the 4 Hydrogens), the geometry of the molecule must be tetrahedral. Tetrahedral moleculues have bond angles of 109.5 Degrees.

6 0
3 years ago
Which sample contains the greater number of atoms, a sample of Li that contains 6.8 x 10^22 atoms or a 1.97 mole sample of Na?
IrinaVladis [17]

Answer:

                     1.97 moles of Na contains greater number of atoms than 6.8 × 10²² atoms of Li.

Explanation:

                    To solve this problem we will first calculate the number of atoms contained by 1.97 moles of Na and then will compare it with 6.8 × 10²² atoms of Li.

                    As we know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of atoms contained by 1.97 moles of Na, we will use following relation,

          Moles  =  Number of Atoms ÷ 6.022 × 10²³ atoms.mol⁻¹

Solving for Number of Atoms,

          Number of Atoms  =  Moles × 6.022 × 10²³ Atoms.mol⁻¹

Putting values,

          Number of Atoms  =  1.07 mol × 6.022 × 10²³ Atoms.mol⁻¹

          Number of Atoms  = 1.18 × 10²⁴ Atoms of Na

Hence,

          1.97 moles of Na contains greater number of atoms than 6.8 × 10²² atoms of Li.

4 0
3 years ago
you run 1 3/4 miles each day. your friend runs 4 times as far as you. how far does your friend runs each day
djverab [1.8K]
1 3/4 * 4 = 7

Your friend runs 7 miles each day.
8 0
3 years ago
Select the best answer.
madreJ [45]
Answer: All of these I’m pretty sure

Explanation: It just makes sense
8 0
3 years ago
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