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7nadin3 [17]
3 years ago
8

If a rectangle is 30 feet long and the perimeter is 78 feet. What would be the width of the rectangle?

Mathematics
1 answer:
mario62 [17]3 years ago
3 0

Answer:

The width should be 9 feet in this situation

Step-by-step explanation:

(30 x 2) + (9 x 2) =

60 + 18 =

78 ft

Or

78 - (30 X 2) =

78 - 60 =

18 / 2 =

9

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mezya [45]

W-1/4= 3/7

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common denominator is 28

Multiply by 4 , top and bottom for 3/7

Multiply by 7 , top and bottom for 1/4

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3 years ago
Solve image below:
ludmilkaskok [199]

Answer: x=\frac{6}{-3y+8}

Step-by-Step Explanation:

Let's solve for x.

\frac{x-2}{3y-5} =\frac{x}{3}

Step 1: Multiply both sides by 3y-5.

x-2=\frac{3xy-5x}{3}

Step 2: Multiply both sides by 3.

3x-6=3xy-5x

Step 3: Add -3xy to both sides.

3x-6+-3xy=3xy-5x+-3xy

-3xy+3x-6=-5x

Step 4: Add 5x to both sides.

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Step 5: Add 6 to both sides.

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Step 6: Factor out variable x.

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Answer:

x=\frac{6}{-3y+8}

4 0
3 years ago
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