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Dmitriy789 [7]
3 years ago
12

Consider a computer that uses 6 bits to represent integers: 1 bit for the sign and 5 bits for the actual number. What's the larg

est positive integer it can represent?
Mathematics
1 answer:
ycow [4]3 years ago
5 0

Answer:

31

Step-by-step explanation:

Therefore, range of 5 bit unsigned binary number is from 0 to (25-1) which is equal from minimum value 0 (i.e., 00000) to maximum value 31 (i.e., 11111).

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What is x?<br> 7(x – 5) = 9x – 3
Mkey [24]

Answer:

x = -16

Step-by-step explanation:

7(x-5) =9x-3 \\7x -35 = 9x - 3\\3- 35 = 9x - 7x\\-32 = 2x\\x = \frac{-32}{2}\\\huge \red{\boxed{x = -16}}

4 0
3 years ago
Read 2 more answers
Hey can I have help?
Alinara [238K]
Should be -24 or 24
8x-3 equals -24. Your correct answer is -24
7 0
3 years ago
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Gary jogs 2/3 of a mile in 1/3 of an hour. how many mipes can he jog in 1 hour?
cricket20 [7]
2 miles.
This is because 2/3 times 3 equals 2.
8 0
3 years ago
I can write numerical expressions involving whole-number exponents
DerKrebs [107]

Answer:

yes

Step-by-step explanation:

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7 0
3 years ago
The following function represents the profit P(n), in dollars, that a concert promoter makes by selling tickets for n dollars ea
Gre4nikov [31]
A) zeroes

P(n) = -250 n^2 + 2500n - 5250

Extract common factor:

P(n)= -250 (n^2 - 10n + 21)

Factor (find two numbers that sum -10 and its product is 21)

P(n) = -250(n - 3)(n - 7)

Zeroes ==> n - 3 = 0  or n -7 = 0
Then n = 3 and n = 7 are the zeros.

They rerpesent that if the promoter sells tickets at 3  or 7 dollars the profit is zero.

B) Maximum profit

Completion of squares

n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4

P(n) = - 250[(n-5)^2 -4] = -250(n-5)^2 + 1000

Maximum ==> - 250 (n - 5)^2 = 0 ==> n = 5 and P(5) = 1000

Maximum profit =1000 at n = 5

C) Axis of symmetry

Vertex = (h,k) when the equation is in the form A(n-h)^2 + k

Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000

Vertex = (5, 1000) and the symmetry axis is n = 5.



8 0
3 years ago
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