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RUDIKE [14]
3 years ago
11

Can i get help please

Mathematics
1 answer:
Olin [163]3 years ago
4 0

Answer:

120x^3

Step-by-step explanation:

exponent rule --> a^b x a^c = a^b+^c

10^-6 x 10^7 = 10^6 + ^7

add / subtract numbers -- > -6 + 7 = 1

=2XX x 6X x 10

aponent rule --> a^b x a^c = a^b+^c

xxx = x^1 + ^1 + ^1

= 2 x 6x^1 + ^1 + ^1 x 10

= 2 x 6x^3 x 10

= 120x^3

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Complete the problem to represent the situation given by the equation 0.40e + 10 + 15 = 0.20e + 5 + 25. At one store a trophy co
olganol [36]

Answer: The number of letters that must be engraved for the costs to be the same is 125.

Step-by-step explanation:

Since we have given that

0.4e+10+15=0.20e+5+25

We need to find the number of letters.

0.4e+25=0.2e+30\\\\0.4e-0.2e=30-25\\\\0.2e=25\\\\e=\dfrac{25}{0.2}\\\\e=125

Hence, the number of letters that must be engraved for the costs to be the same is 125.

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3 years ago
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Answer:

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I don't know what to do! please help!<br>​
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Answer:

128

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2 years ago
What is the solution (a, c) to this system of linear equations?
Akimi4 [234]
Method:

Simultaneous equations

Explanation:

First we will need to get both equations to have the same subject, to do this we will multiply the bottom equation by 2.

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Now we will make both equations equal to the same subject (2a)

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3 years ago
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