All categories

3 years ago

Find x X= Can someone pls help

Mathematics

1 answer:

garik1379 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

Evaluate f(2). f(x)=3x-1

amid [387]

It’s going to be 2..

6 0

3 years ago

so a group of students are in a club. half are boys ,4/9 of the boys have brown eyes. how many boys have brown eyes?

aliina [53]

it will have to be 5/9 or0.5555555556

8 0

4 years ago

Find the perimeter of each of the two non congruent triangles where a=15,b=20 and a=29

Alborosie

Answer:

b. about 63.9 units and 41.0 units

Step-by-step explanation:

In question ∠a= 29° and Side of a= 15 and b= 20

Using sine rule of congruence of triangle.

⇒ $\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}$

⇒ $\frac{15}{Sin 29} = \frac{20}{sin B}$

Using value of sin 29°

⇒ $\frac{15}{0.49} = \frac{20}{sin B}$

Cross multiplying both side.

⇒ Sin B= $\frac{20\times 0.49}{15} = 0.65$

∴ B= 41°

Now, we have the degree for ∠B= 41°.

Next, lets find the ∠C

∵ we know the sum total of angle of triangle is 180°

∴∠A+∠B+∠C= 180°

⇒ $29+41+B= 180$

subtracting both side by 70°

∴∠C= 110°

Now, again using the sine rule to find the side of c.

$\frac{b}{SinB} = \frac{c}{SinC}$

⇒ $\frac{20}{sin41} = \frac{C}{sin110}$

Using the value of sine and cross multiplying both side.

⇒ C= $\frac{20\times 0.94}{0.65} = 28.92$

∴ Side C= 28.92.

Now, finding perimeter of angle of triangle

Perimeter of triangle= a+b+c

Perimeter of triangle= $(15+20+28.92)= 63.9$

∴ Perimeter of triangle= 63.9 units

7 0

3 years ago

4sin²<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B2%7D" id="TexFormula1" title="\frac{x}{2}" alt="\frac{x}{2}" align="absm

raketka [301]

Answer:

$\displaystyle x=\left \{\frac{2\pi}{3}+2\pi k,\frac{4\pi}{3}+2\pi k, \frac{8\pi}{3}+2\pi k, \frac{10\pi}{3}+2\pi k\right \}k\in \mathbb{Z}$

Step-by-step explanation:

Hi there!

We want to solve for $x$ in:

$4\sin^2(\frac{x}{2})=3$

Since $x$ is in the argument of $\sin^2$ , let's first isolate $\sin^2$ by dividing both sides by 4:

$\displaystyle \sin^2\left(\frac{x}{2}\right)=\frac{3}{4}$

Next, recall that $\sin^2x$ is just shorthand notation for $(\sin x)^2$ . Therefore, take the square root of both sides:

$\displaystyle \sqrt{\sin^2\left(\frac{x}{2}\right)}=\sqrt{\frac{3}{4}},\\\sin\left(\frac{x}{2}\right)=\pm \sqrt{\frac{3}{4}}$

Simplify using $\displaystyle \sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}$ :

$\displaystyle \sin\left(\frac{x}{2}\right)=\pm \sqrt{\frac{3}{4}},\\\sin\left(\frac{x}{2}\right)=\pm \frac{\sqrt{3}}{\sqrt{4}}=\pm \frac{\sqrt{3}}{2}$

Let $\phi = \frac{x}{2}$ .

<h3><u>Case 1 (positive root):</u></h3>

$\displaystyle \sin(\phi)=\frac{\sqrt{3}}{2},\\\phi = \frac{\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\phi =\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z}$

Therefore, we have:

$\displaystyle \frac{x}{2}=\phi = \frac{\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\frac{x}{2}=\phi =\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z},\\\\\begin{cases}x=\boxed{\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z}},\\x=\boxed{\frac{4\pi}{3}+2\pi k , k \in \mathbb{Z}}\end{cases}$

<h3><u>Case 2 (negative root):</u></h3>

$\displaystyle \sin(\phi)=-\frac{\sqrt{3}}{2},\\\phi = \frac{4\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\phi =\frac{5\pi}{3}+2\pi k, k\in \mathbb{Z},\\\begin{cases}x=\boxed{\frac{8\pi}{3}+2\pi k, k\in \mathbb{Z}},\\x=\boxed{\frac{10\pi}{3}+2\pi k , k \in \mathbb{Z}}\end{cases}$

8 0

3 years ago

Major League Baseball now records information about every pitch thrown in every game of every season. Statistician Jim Albert co

taurus [48]

Fastballs i believe

7 0

3 years ago