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saw5 [17]
3 years ago
9

I need help ASAP PLSSSSS.​

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
6 0

Answer:

Step-by-step explanation:

I dont know if its right but I think you have to subtract 30% from seven since the equation is not being specific and I came up with 4.9 but dont quote me on it im just giving a educational guess

MrRa [10]3 years ago
3 0

Answer:

70

Step-by-step explanation:

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Compare 8^0 and 8^-2. which is greater? Explain your reasoning.
aev [14]

Hello there!

8^0 amd 8^-2


Let me start with 8^-2

8^-2 = 1/8 * 8

8^-2 = 1/64

which equals to 0.015625 in decimal


8^ 0 =  1

Yep, that's the answer! Easy, isn't? Well you may have been wondering why 8^0 is equal to 1.

I quoted an explanation online that says:    Think of "multiplication" as always including an extra "1" as a multiplier.

So it'd be like

8^ 0

8/8 = 1


Remember: Whenever a number has an exponent 0, the answer MUST be 1.


Thus,

8^0 is greater. As you can see, it is equal to 1, while the other one is equal to 0.01


I'm terrible at explaining stuff. I hope you find this answer somehow helpful :)

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4 years ago
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150pounds = what in kilograms
Minchanka [31]

this is your answer.

Answer: 68.0389

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2 years ago
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Geometry section 1.1 :)
Olegator [25]

Answer: C. 14

Step-by-step explanation:

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3 years ago
What is the simplest form for 6/8
daser333 [38]

3/4

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4 years ago
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Write an algebraic expression that is the quotient of a variable term and a constant.
docker41 [41]

9514 1404 393

Answer:

  (47xy)/(6√3)

Step-by-step explanation:

A variable term is one that contains one or more variables, possibly with a coefficient. We can use 47xy as our variable term.

A constant is some number, or a representative of a particular number. π and e and Ф are representative of irrational constants. Of course, any number is also a constant. We can use 6√3 as our constant.

A quotient is formed when a first value is divided by a second value.

Here is the quotient of our variable term and our constant:

  \dfrac{47xy}{6\sqrt{3}}

4 0
3 years ago
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