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STALIN [3.7K]
3 years ago
9

Given the diagram below, find X. The diagram IS 40° x - 15° X = degrees.

Mathematics
1 answer:
Crank3 years ago
6 0

Answer:

X=65°

Step-by-step explanation:

Both angles combined is a right angle as indicated by the small square drawn on it, a right angle is always 90° therefore

(x-15°)+40°=90°

combine like terms

x+25°=90°

subtract 25° from each side

x=65°

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Kayla charges $15 for a bracelet, plus $0.80 for each letter bead that is put on the bracelet. Which expression represents the t
zmey [24]

Answer:

The answer is 15.00+0.80x

Step-by-step explanation:

I know because I just did this question Lol-

7 0
2 years ago
In a widget factory, machines A, B, and C manufacture, respectively, 20, 30, and 50 percent of the total. Of their output 6, 3,
steposvetlana [31]

Answer:

38.71% probability it was manufactured by machine A.

29.03% probability it was manufactured by machine B.

32.26% probability it was manufactured by machine C.

Step-by-step explanation:

We have these following probabilities:

A 20% probability that the chip was fabricated by machine A.

A 30% probability that the chip was fabricated by machine B.

A 50% probability that the chip was fabricated by machine C.

A 6% probability that a chip fabricated by machine A was defective.

A 3% probability that a chip fabricated by machine B was defective.

A 2% probability that a chip fabricated by machine C was defective.

The question can be formulated as:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

What are the probabilities that it was manufactured by machines A, B, and C?

Machine A

What is the probability that the widget was manufactures by machine A, given that it is defective?

P(B) is the probability that it was manufactures by machine A. So P(B) = 0.20

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine A. So P(A/B) = 0.06

P(A) is the probability that a widget is defective. This is the sum of 6% of 20%, 3% of 30% and 2% of 50%. So

P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.2*0.06}{0.031} = 0.3871

38.71% probability it was manufactured by machine A.

Machine B

What is the probability that the widget was manufactures by machine B, given that it is defective?

P(B) is the probability that it was manufactures by machine B. So P(B) = 0.30

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine B. So P(A/B) = 0.03

P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.3*0.03}{0.031} = 0.2903

29.03% probability it was manufactured by machine B.

Machine C

What is the probability that the widget was manufactures by machine C, given that it is defective?

P(B) is the probability that it was manufactures by machine C. So P(B) = 0.50

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine C. So P(A/B) = 0.02

P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.5*0.02}{0.031} = 0.3226

32.26% probability it was manufactured by machine C.

6 0
3 years ago
Sandy threw a ball 86 inches. She
Vanyuwa [196]
She threw the ball 84 inches
8 0
2 years ago
Carl wants to plant a garden that is 1 1/2 yard long with an area of 3 1/2 square yards. What is the width of the garden?
BARSIC [14]

Answer:

2 1/3

Step-by-step explanation:

You divide 3 1/2 by 1 1/2

7 0
3 years ago
Answers to question 5 and 6 please xx
Temka [501]
5a) a
5b) 3a
5c) b
5d) a²/b
5e) 4ab
5f) a           (take out the a, from both (bring to outside) cancel the rest
6a)8a^5
6b)15b^7
6c)24a^4b^2
6j)18a^4b^9


hope this helps
8 0
3 years ago
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