Answer:
false
Explanation:
Ms word is only an application software
Answer:
- Information services and support
- Programming and software development
- Network systems administration
Explanation:
The company has finished designing a software program, but users aren’t sure how to use it. <u>interactive media</u>
Several people in the human resources department need new software installed. <u>information services and support</u>
An employee has an idea for a software program that can save the company time, but doesn’t know how to write it. <u> programming and software development</u>
A new branch of the company is opening soon, and the computers there need to be connected to the Internet. <u>network systems administration</u>
<u>OAmalOHopeO</u>
The command is Export-NpsConfiguration
An admin can export the entire NPS configuration from one NPS for import to another NPS. Standard precautions should be taken when exporting NPS configurations over the network. The command syntax that can be used for exporting the NPS configurations is Export-NpsConfiguration –Path <filename>
Answer:
#include <iostream>
using namespace std;
class Str{ ///baseclass
public :
string super_str;
string getStr()
{
return super_str;
}
void setStr(string String)
{
super_str=String;
}
};
class str : public Str{ //inheriting Str publicly
public :
string sub_str;
string getstr()
{
return sub_str;
}
void setstr(string String)
{
sub_str=String;
}
bool notstartswith()
{
int n=sub_str.length(); //to find length of substr
bool flag=false;
for(int i=0;i<n;i++) //Loop to check beginning of Str
{
if(super_str[i]!=sub_str[i])
{
flag=true;
break;
}
}
return flag;
}
};
int main()
{
str s; //object of subclass
s.setStr("Helloworld");
s.setstr("Hey");
if(s.notstartswith()==1) //checking if str is substring of Str
cout<<"Str does not start with str";
else
cout<<"Str starts with str";
return 0;
}
OUTPUT :
Str does not start with str
Explanation:
Above program is implemented the way as mentioned. for loop is being used to check the beginning of the str starts with substring or not.
