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3 years ago

Can Someone please help me I am very confused

Mathematics

1 answer:

denis-greek [22]3 years ago

8 0

Answer:

bro

Step-by-step explanation:

honestly just guess lol if someone gives you a good answer well use it

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Suppose a triangle has sides a, b, and c, and let theta be opposite the side of length a. If cos theta < 0, what must be true

katrin2010 [14]

If $\cos \theta\ \textless \ 0$ , then angle $\theta$ is obtuse and triangle with sides a, b, c is obtuse triangle.
In an arbitrary triangle can be only one obtuse angle, and the side which lies opposite to the largest angle is the largest. Then since angle $\theta$ is opposite the side of length a you can conclude that a>c and a>b.

6 0

4 years ago

Which type of triangle, if any, has side lengths of 11, 15, and 25?

abruzzese [7]

Answer:

Scalene triangle

Step-by-step explanation:

An equilateral triangle has 3 equal sides.

An isosceles triangle has 2 equal sides.

A scalene triangle has no equal sides.

4 0

3 years ago

Read 2 more answers

1. The exponential function modeled below represents the number of square

Umnica [9.8K]

Answer:

600,000 km²

Step-by-step explanation:

Using the exponential regression calculator : the regression fit obtained for the data is :

36510 * (1.08^x)

After 40 years ;

x = 40

Hence,

y = 36510 * 1.08^40

y = 36510 * 21.72452

y = 793,162.27 km

Hence, y is closest to 800,000 km

7 0

3 years ago

What is the solution to –2(8x – 4) < 2x + 5?

Contact [7]

The solution to –2(8x – 4) < 2x + 5 is x > 1/6

<h3>How to solve the inequality?</h3>

The expression is given as:

–2(8x – 4) < 2x + 5

Expand

-16x + 8 < 2x + 5

Evaluate the like terms

-18x < -3

Divide both sides by -18

x > 1/6

Hence, the solution to –2(8x – 4) < 2x + 5 is x > 1/6

Read more about inequalities at:

brainly.com/question/11613554

#SPJ1

4 0

2 years ago

I xyzdS trong đó S là phần mặt 2 2 z x y nằm giữa hai mặt phẳng z = 0 và z = 1

Anni [7]

Step-by-step explanation:

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$= . { {y1 {11.1 \times 3 { { {?}^{?} }^{?} }^{?} }^{?} }^{2} }^{2}$

vadbstjtwjsgjdgndymarhedvdhstjwtktwdgharjqrjwrjgjtkstjtsjafbsfnafhafbsfhtshqwdgjwjdjdnnxnxifjnrnthrwhst

$22 {y)bvzv \cot( \beta log( \sec( log( \cot( \sec( \beta \alpha \pi \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( log(?) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) \times \frac{?}{?} }^{2}$

hfzbcEdfgaywjshhsbxbxbxb. seznnxndndnndnxnbxhxududhbdxhhbxhjxjdbnzjsnsnnznzidnxnsbnzjxldkdjdnbx

4 0

3 years ago