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mario62 [17]
3 years ago
6

When twice a number is subtracted from 34, the result is 16. Find the number.

Mathematics
2 answers:
Schach [20]3 years ago
7 0

Answer:

9

Step-by-step explanation:

34 - 16 = 18

18 ÷ 2 = 9

you're welcome! I'm a 6th grader btw!

ch4aika [34]3 years ago
7 0

Answer:

9

Step-by-step explanation:

34-2x=16

-2x=16-34

-2x=-18

2x=18

X=18/2

X=9

So the answer is 9.

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1)cot a/2 -tan a/2 = 2 cot a<br>2) cot b/2 + tan b/2= 2 cosec b<br> prove​
VladimirAG [237]
1)

LHS = cot(a/2) - tan(a/2)

= (1 - tan^2(a/2))/tan(a/2)

= (2-sec^2(a/2))/tan(a/2)

= 2cot(a/2) - cosec(a/2)sec(a/2)

= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))

= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)

= 2[(1+cos(a) -1)/sin(a)]

=2cot a

= RHS

2.

LHS = cot(b/2) + tan(b/2)

= [1 + tan^2(b/2)]/tan(b/2)

= sec^2(b/2)/tan(b/2)

= 1/sin(b/2)cos(b/2)

using product to sums

= 2/sin(b)

= 2cosec(b)

= RHS
8 0
3 years ago
Solve for x:<br> -3(x-2)^2+17=0 <br> round your answer to the nearest hundredth
kicyunya [14]

Answer:

-3(x-2)×2+17=0

  1. -3x+6×2+17=0
  2. -3x+12+17=0
  3. -3x+29=0
  4. -3x=0-29=-29
  5. -3x=-29
  6. 29÷3=9.700 to the nearest hundredth
8 0
2 years ago
A rectangular box has a square base. The combined length of a side of the square base, and the height is 20 in. Let x be the len
aniked [119]

Answer:

a. V = (20-x) x^{2} in^{3}  

b . 1185.185 in^{3}

Step-by-step explanation:

Given that:

  • The height:  20  - x (in )
  • Let x be the length of a side of the base of the box (x>0)

a. Write a polynomial function in factored form modeling the volume V of the box.

As we know that, this is a rectangular box has a square base so the Volume of it is:

V = h *x^{2} in^{3}

<=> V = (20-x) x^{2}  in^{3}

b. What is the maximum possible volume of the box?

To  maximum the volume of it, we need to use first derivative of the volume.

<=> dV / Dx = -3x^{2} + 40x

Let dV / Dx = 0, we have:

-3x^{2} + 40x  = 0

<=> x = 40/3

=>the height h = 20/3

So  the maximum possible volume of the box is:

V = 20/3 * 40/3 *40/3

= 1185.185 in^{3}

7 0
3 years ago
HELP PLEASE 18 POINTS
Mrrafil [7]

Answer:

75000 centigrams

Step-by-step explanation:

5 0
3 years ago
"at the end of the year Juan has $52.71 more than 4 times his balance at the beginning of the year if his ending balance was $17
Salsk061 [2.6K]
At the end of the year, Juan has 52.71 more than 4 times his balance at the beginning. Okay, let's set this up.

4x + 52.71
(4 times) (52.71 more)
His ending was 172.90, so
4x + 52.71=172.90
4x= 120.19
x= 30.05
He had $30.05 at the beginning of the year.
8 0
3 years ago
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