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IrinaVladis [17]
3 years ago
12

Which of the following shows why the commutative property doesn't work under subtraction

Mathematics
2 answers:
Annette [7]3 years ago
5 0
Hello!  To answer your question, you first need to know what the commutative property is and does.  Down to the basics, it lets you switch around numbers and it would allow me to say that 2+5=7 and 5+2=7.  This property also works in multiplication, because if I take 4*2=8, and 2*4 still equals 8.  Now that I've either refreshed or hopefully helped you to understand the property better, why wouldn't it work under subtraction?  If you switch numbers around in subtraction, will your answer still be the same?  Once you answer that, take a peak at the worksheet!  I hope this has helped in some way, and if you have any further questions send me a question or another message.  Good luck :)
siniylev [52]3 years ago
3 0

Answer with explanation:

Commutative property under subtraction:

If a and b are any two real numbers such that,⇒ a-b =b-a, then we say that ,a and b Satisfy Commutative property under Subtraction.

Take any two real numbers

a=5.6

And,b=7

→a-b

=5.6-7

= -1.4

→b-a

=7-5.6

=1.4

So,a-b≠b-a

Therefore  , we can say that, real numbers doesn't satisfy commutative property under subtraction.

Option D: ⇒5-1≠1-5

This statement shows that, commutative property doesn't work under subtraction.

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Answer:

The correct option is C.

Step-by-step explanation:

The quadratic parent function is

f(x)=x^2

The translation is defined as

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Where, k is vertical stretch, a is horizontal shift and b is vertical shift.

If |k|>1, then graph of parent function stretch vertically by factor |k| and if 0<|k|<1, then parent function compressed vertically by factor |k|. Negative k represents the reflection across x axis.

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If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

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