Can someone help me please? Would really appreciate it!
1 answer:
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Answer:
1.2%
Step-by-step explanation:
We are given that the students receive different versions of the math namely A, B, C and D.
So, the probability that a student receives version A = .
Thus, the probability that the student does not receive version A = =
.
So, the possibilities that at-least 3 out of 5 students receive version A are,
1) 3 receives version A and 2 does not receive version A
2) 4 receives version A and 1 does not receive version A
3) All 5 students receive version A
Then the probability that at-least 3 out of 5 students receive version A is given by,
+
+
=
=
=
=
= 0.01171875 × 1.0625
= 0.01245
Thus, the probability that at least 3 out of 5 students receive version A is 0.0124
So, in percent the probability is 0.0124 × 100 = 1.24%
To the nearest tenth, the required probability is 1.2%.