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EastWind [94]
3 years ago
10

HURRY PLEASE

Mathematics
2 answers:
Sever21 [200]3 years ago
8 0
C is the answer for this
bogdanovich [222]3 years ago
6 0

Answer: c

Step-by-step explanation:

ewefwef

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A ball is thrown from a height of 139 feet with an initial downward velocity of 15 ft/s. The ball's height h (in feet) after t s
ella [17]

Answer:

t = 2.52 seconds

Step-by-step explanation:

h=139-15t-16t^2

We want to know when the ball hits the ground

That would be when h=0

0 = 139-15t-16t^2

We can use the quadratic formula to find t

t = -b ± sqrt(b^2-4ac)

       ----------------------

          2a

where a = -16   b = -15  and c = 139

t = -(-15) ± sqrt((-15)^2-4(-16)139)

       ----------------------

          2(-16)

t = (15) ± sqrt(225+8896)

       ----------------------

          -32

t = (15) ± sqrt(9121)

       ----------------------

          -32

t = 15+ sqrt(9121)                       t = 15- sqrt(9121)

     --------------------   or                    -------------------  

           -32                                               -32

        -3.453247707        or              2.515747707

Since time cannot be negative

 2.515747707

Round to the nearest hundredth

t = 2.52 seconds

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Using the diagram below, translate the figure 3 units to the left and 2 units up. Graph the translated figure and provide the tr
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Step-by-step explanation:

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