First, find what percentage of students had 3 or more by adding up your known percents:
45% + 23 % + 21% + x% = 100%
x = 11%
Since you're given that 96 students had 2 or more, you add up the percentages of 2 and 3 or more:
11 + 21 = 32%
Now set up a proportion that relates it to the whole:

This will allow you to find the total number of students at the school.
Cross multiplying and solving for x results in 300 total students.
Question 1:
45% had one or more absences. 45% of 300 students is
135 students.
Question 2:
As we found before, 11% of students had three or more. 11% of 300 is
33 students.
The equation is b-a= 21;
2b-5a = 18
a=8 and b= 29
therefore 29-8= 21
2 (29) -5 (8) = 18
58-40=18
Answer:
99
Step-by-step explanation:
Since given, < 100.
So,
100 - 1 = 99
Yes. This is true because 4 subtracted from 8 is 8-4=4. The value you get from subtracting 4 from 8 equals the same value you would get if you were to take the value of 2 and square it. Both equal 4.
If she can drive 4180 miles in <em>two </em>weeks, it would make sense that she would drive an average of <em>half </em>that distance in <em>one </em>week. Half of 4180 is 2090, so she averaged 2090 miles each week.