Let numbers be x and y
ATQ
Adding both
Now putting value in eq(2)
Answer:
Width = 15 feet
Length = 45 feet
Step-by-step explanation:
You need to fence in a rectangular piece of land for your dog to run and play. The length is 3 times the width. If the perimeter is 120 ft, what are the dimensions of your very own dog park?
Perimeter of a rectangle = 2L + 2W
The length is 3 times the width.
L = Length = 3W
W = Width
P = 120 ft
Hence:
120 = 2L + 2W
120 = 2(3W) + 2W
120 = 6W + 2W
120 = 8W
W = 120/8
W = 15 feet
Solving for Length
L = 3W
L = 3 × 15 feet
L = 45 feet
Therefore, the dimensions of your very own dog park is
Width = 15 feet
Length = 45 feet
I think it is 9 6/9 but im not quite sure .
