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Nataly [62]
3 years ago
9

A group of friends spent 1, 0, 2, 3, 4, 3, 6, 1, 0, 1, 2, and 2 hours online last night. What are the 1st and 3rd quartiles for

this set of data?
Mathematics
1 answer:
charle [14.2K]3 years ago
8 0
1 and 3 i just did the math tell me if i’m wrong
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What is the value of b in this equation?<br><br> A. -20<br> B. -6<br> C. 6<br> D. 20
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Answer:

Step-by-step explanation:

a- 12

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and the next part is

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Verify the identity. cot(x - pi/2) = -tan(x)
gizmo_the_mogwai [7]

Answer:

See below.

Step-by-step explanation:

\cot(x-\frac{\pi}{2})=-\tan(x)

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\frac{\cos(x-\frac{\pi}{2} )}{\sin(x-\frac{\pi}{2})} =-\tan(x)

Use the cofunction identities. The cofunction identities are:

\sin(x)=\cos(\frac{\pi}{2}-x)\\\cos(x)=\sin(\frac{\pi}{2}-x)

To convert this, factor out a negative one from the cosine and sine.

\frac{\cos(-(\frac{\pi}{2}-x ))}{\sin(-(\frac{\pi}{2}-x))} =-\tan(x)

Recall that since cosine is an even function, we can remove the negative. Since sine is an odd function, we can move the negative outside:

\frac{\cos((\frac{\pi}{2}-x ))}{-\sin((\frac{\pi}{2}-x))} =-\tan(x)\\-\frac{\sin(x)}{\cos(x)} =-\tan(x)\\-\tan(x)\stackrel{\checkmark}{=}-\tan(x)

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3 years ago
If m∠A = m∠B and m∠A + m∠C = ∠D, then m∠B + m∠C = ∠D Which property is shown?
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Step-by-step explanation:

So we know that:

m\angle A=m\angle B

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m\angle A+m\angle C=\angle D

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m\angle B+m\angle C=\angle D

Essentially, we <em>substituted</em> B for A.

So, this is an example of the substitution property, where if two sides/angles are congruent, we can substitute them for each other.

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