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Furkat [3]
3 years ago
15

There were a total of 209 basketball games in the season the season played is for 19 months how many basketball games were playe

d each month if each month has the same number of games?
Mathematics
2 answers:
GenaCL600 [577]3 years ago
8 0

Answer:11

Step-by-step explanation:Because 209 divided by 19

dangina [55]3 years ago
6 0

Answer:

11

Step-by-step explanation:

divide 209 by 19 to get an equal number of games each month (for 19 months), you will get 11 games each month.

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For two apply A and B, P(A)=0.5,and P(A|B)=0.7. Select all of the correct statements
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What is the greatest factor of 49 that is a prime number
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What is the greatest common factor of 44c^5, 22c^3 and 11c^4
Alexxandr [17]

\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

<em><u>Solution:</u></em>

Given that, we have to find the greatest common factor of 44c^5, 22c^3 , 11c^4

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}

First find the GCF of numbers and then find the GCF of variables and then multiply them together

<em><u>Step 1: GCF of 44, 22 and 11</u></em>

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

\text{ Step 2: GCF of }c^5, c^3 , c^4

c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1

Thus the greatest common factor is c^3

Step 3: Multiply the GCF of 44, 22, 11 and GCF of c^5, c^3 , c^4

\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3

Thus \text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

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3 years ago
Can any one help me in this please any math genius
andriy [413]
It is 10 to 1 significant figures
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