Answer:
The overall change in field position is 7yds, 0 - 5 + 12 = 7, if that isn't a "sum of integers" I apologize.
Step-by-step explanation:
True, each number is getting doubled, both sides are proportionally staying the same.
Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
Answer:
Step-by-step explanation:
<u>Given</u>
<u>Substitute and solve for n:</u>
- 42 = n² + n
- n² + 2*1/2n + 1/4 = 42.25
- (n + 0.5)² = 42.25
- n + 0.5 = √42.25
- n + 0.5 = 6.5
- n = 6
Correct option is C
Answer:
p= 1/3 or 0.33 repeating
Step-by-step explanation:
5-19p=-p-1
5=18p-1
6=18p
divide by 18
6/18 = 1/3 or 0.33 repeating