C^2=a^2+b^2 we are given the hypotenuse of 19 units and one leg of 8 units so:
19^2=8^2+b^2
361=64+b^2
b^2=297
b=√297
b≈17.2 to the nearest tenth
Answer:
<h3>Length = 29 inches</h3><h3>Width = 8 inches</h3><h3 />
Step-by-step explanation:
Perimeter of a rectangle = 2l + 2w
where
l is the length of the rectangle
w is the width
From the question
length of a rectangular picture is 5 inches more than three times the width is written as
l = 5 + 3w
Now substitute this into the above equation
Perimeter = 74 inches
74 = 2(5 + 3w) + 2w
74 = 10 + 6w + 2w
8w = 74 - 10
8w = 64
Divide both sides by 8
w = 8 inches
Substitute w = 8 into l = 5 + 3w
That's
l = 5 + 3(8)
l = 5 + 24
l = 29 inches
<h3>Length = 29 inches</h3><h3>Width = 8 inches</h3>
Hope this helps you
First, multiply -6*-5. This equals (positive) 30 because the negative signs cancel out.
This leaves you with:
30+12
Doing the addition leaves you with 42.
The answer is 42.
I hope this helps :)
Answer:
Step-by-step explanation:
Begin by squaring both sides to get rid of the radical. Doing that gives you:
Now use the Pythagorean identity that says
and make the replacement:
. Now move everything over to one side of the equals sign and set it equal to 0 so you can factor:
and then simplify to
Factor out the common cos(x) to get
and there you have your 2 trig equations:
cos(x) = 0 and 1 - cos(x) = 0
The first one is easy enough to solve. Look on the unit circle and see where, one time around, where the cos of an angle is equal to 0. That occurs at
The second equation simplifies to
cos(x) = 1
Again, look to the unit circle and find where the cos of an angle is equal to 1. That occurs at π only.
So, in the end, your 3 solutions are
