Answer:
Which is the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 respectively? 204.
Step-by-step explanation:
Have a great summer.
204 is the smallest number.
28 - 8 = 20 and 32 - 12 = 20
The required number will be 20 less than the LCM of 28 and 32.
Prime factorization of 28,
→ 2 × 2 × 7
Prime factorization of 32,
→ 2 × 2 × 2 × 2 × 2
LCM(28, 32) = 2 x 2 x 2 x 2 x 2 x 7 = 224
Hence, the required smallest number,
→ 224 - 20 = 204
it's B it could also be written as y=3x+30
Answer: 112
2x+3x+10=180
5x=170
x=34
3x+10=112
By Geometric mean property:
