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sergij07 [2.7K]
3 years ago
10

Can someone help me answer this please

Mathematics
2 answers:
shepuryov [24]3 years ago
5 0

Answer:

11.45 years

Step-by-step explanation:

22 inch ÷ 21 inch = 1.0476190476

Difference between Type A and B 12 inch

= 12 inch ÷ 1.0476190 = 11.454545

Will take 11.45 years to cover 12 inch of Type B

So,

Type B

21 inch per year × 11.45 years + 36 inch= 276.45 inch or 276 inch or 23 Feet.

Type A

22 inch ×11.45 years + 24 inch = 275.9 inch or 276 inch Or 23 Feet.

Maru [420]3 years ago
4 0

Answer:

3 years

Step-by-step explanation:

set two equations in inches and equate

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Let the first investment be x
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4 years ago
Select all of the potential solution(s) of the equation 2log5x = log54.
Vanyuwa [196]

Answer:

x = ±2

Step-by-step explanation:

A equation is given to us , which is ,

\longrightarrow 2log_5(x) = log_5 4

From <u>properties </u><u>of </u><u>logarithm </u>we know that ,

\longrightarrow alog\ m = log \ m^a

Applying this to LHS , we have ;

\longrightarrow log_5 x^2 = log_5 4

Now the bases of logarithm on LHS and RHS is same . On comparing , we have ;

\longrightarrow x^2 = 4

Put square root on both sides,

\longrightarrow x =\sqrt{4}

Simplify ,

\longrightarrow \underline{\underline{ x =\pm 2 }}

This is the required answer.

6 0
2 years ago
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3 0
4 years ago
What is the value of -16 divided by 2.5
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3 years ago
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Morgarella [4.7K]

\text{mass of freight train} = 9.98 \times  {10}^{6} kg

\text{mass of aircraft carrier} = 7.3 \times  {10}^{7}  \: kg

\text{difference of masses of aircraft and train: } \\  \\ 7.3 \times  {10}^{7}  - 9.98 \times  {10}^{6}  \\  \\  = 73 \times  {10}^{6}  - 9.98 \times  {10}^{6}

= (73 - 9.98 )\times  {10}^{6}  \\  \\  = 63.02 \times  {10}^{6}  \\  \\  = 6.302 \times  {10}^{6}  \: kg \\  \\  \approx 6.3 \times  {10}^{6}  \: kg

Approximately, aircraft carrier is 6.3 × 10^6 kg heavier than the freight train.
7 0
3 years ago
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