Let point (x, y) be any point on the graph, than the distance between (x, y) and the focus (3, 6) is sqrt((x - 3)^2 + (y - 6)^2) and the distance between (x, y) and the directrix, y = 4 is |y - 4|
Thus sqrt((x - 3)^2 + (y - 6)^2) = |y - 4|
(x - 3)^2 + (y - 6)^2 = (y - 4)^2
x^2 - 6x + 9 + y^2 - 12y + 36 = y^2 - 8y + 16
x^2 - 6x + 29 = -8y + 12y = 4y
(x - 3)^2 + 20 = 4y
y = 1/4(x - 3)^2 + 5
Required answer is f(x) = one fourth (x - 3)^2 + 5
Answer:
1 :
Step 2 :
Equations which are never true :
2.1 Solve : 2 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
2.2 Solve : 2x+1 = 0
Subtract 1 from both sides of the equation :
2x = -1
Divide both sides of the equation by 2:
x = -1/2 = -0.500
One solution was found :
x = -1/2 = -0.500
Answer:
y = 89 x = 123
Step-by-step explanation:
since they're both in standard form, its easier to do the process of elimination
x - y = 34
-x -y -212
------------------
-2y = -178
y = 89
now plug in y to any one of those two equations
x - y = 34
x - 89 = 34
x = 123
<em>to check:</em>
<em>x</em><em> </em><em>+</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>2</em><em>1</em><em>2</em>
<em>1</em><em>2</em><em>3</em><em> </em><em>+</em><em> </em><em>8</em><em>9</em><em> </em><em>=</em><em> </em><em>2</em><em>1</em><em>2</em>
<em>2</em><em>1</em><em>2</em><em> </em><em>=</em><em> </em><em>2</em><em>1</em><em>2</em>
Answer:

Step-by-step explanation:
Given

--- missing from question
Required
Evaluate
We have:

Substitute for x and y



Answer:
3(9+r)
Step-by-step explanation:
pretty sure that should be it if not then mb