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3 years ago

5

A definition for the therm of weight

2 answers:

exis [7]3 years ago

6 0

A body's relative mass or the quantity of matter contained by it, giving rise to a downward force; the heaviness of a person or thing.

oksano4ka [1.4K]3 years ago

4 0

I think relative mass

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Find the 2th term of the expansion of (a-b)^4.

vladimir1956 [14]

The second term of the expansion is $-4a^3b$ .

Solution:

Given expression:

$(a-b)^4$

To find the second term of the expansion.

$(a-b)^4$

Using Binomial theorem,

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here, a = a and b = –b

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

Substitute i = 0, we get

$$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4$

Substitute i = 1, we get

$$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b$

Substitute i = 2, we get

$$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}$

Substitute i = 3, we get

$$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}$

Substitute i = 4, we get

$$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}$

Therefore,

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

$=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}$ $=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}$

Hence the second term of the expansion is $-4a^3b$ .

3 0

3 years ago

What is a typical age (the mean) for the people who were at Movie A?

Snowcat [4.5K]

It is 39

Because you have to count the little dots all the way till it is around the most age.

7 0

2 years ago

Using fluorescent imaging techniques, researchers observed that the position of binding sites on HIV peptides is approximately N

konstantin123 [22]

Answer:

The values is

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 2.45$

The standard deviation is $\sigma = 0.35 \ mi$

The random value is $x = 2.03$

The standardized score for a binding site position of 2.03 microns is mathematically represented as

$z-score = \frac{x - \mu}{ \sigma }$

=> $z-score = \frac{2.03 - 2.45}{ 0.35}$

=> $z-score = -1.2$

7 0

3 years ago

A plane can fly 11 miles per minute. The plane will fly 6 trips, and each trip is 500 miles. How many hours will the plane fly?

Kamila [148]

$\frac{500miles}{trip}\times6trips=3000miles$
$\frac{300miles}{\frac{11miles}{minute}}=272.72minue\approx4.54hrs$

4 0

3 years ago

Find the value of x and y

Zolol [24]

2x=9-y
3y=x-8

y=9-2x
3(9-2x)=x-8

27-6x=x-8
35=7x
x=5

2*5=9-y
10=9-y
y-1

7 0

3 years ago