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Sedaia [141]
3 years ago
5

A definition for the therm of weight

Mathematics
2 answers:
exis [7]3 years ago
6 0
A body's relative mass or the quantity of matter contained by it, giving rise to a downward force; the heaviness of a person or thing.
oksano4ka [1.4K]3 years ago
4 0
I think relative mass
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Find the 2th term of the expansion of (a-b)^4.​
vladimir1956 [14]

The second term of the expansion is -4a^3b.

Solution:

Given expression:

(a-b)^4

To find the second term of the expansion.

(a-b)^4

Using Binomial theorem,

(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}

Here, a = a and b = –b

$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}

Substitute i = 0, we get

$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4

Substitute i = 1, we get

$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b

Substitute i = 2, we get

$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}

Substitute i = 3, we get

$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}

Substitute i = 4, we get

$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}

Therefore,

$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}

=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}

Hence the second term of the expansion is -4a^3b.

3 0
3 years ago
What is a typical age (the mean) for the people who were at Movie A?
Snowcat [4.5K]

It is 39

Because you have to count the little dots all the way till it is around the most age.

7 0
2 years ago
Using fluorescent imaging techniques, researchers observed that the position of binding sites on HIV peptides is approximately N
konstantin123 [22]

Answer:

The values is  

Step-by-step explanation:

From the question we are told that

  The population mean is  \mu  =  2.45

    The  standard deviation is  \sigma  = 0.35 \ mi

     The random value is  x =   2.03

The standardized score for a binding site position of 2.03 microns is mathematically represented as

       z-score  =  \frac{x -  \mu}{ \sigma }

=>      z-score  =  \frac{2.03 -  2.45}{ 0.35}

=>    z-score  =  -1.2

7 0
3 years ago
A plane can fly 11 miles per minute. The plane will fly 6 trips, and each trip is 500 miles. How many hours will the plane fly?
Kamila [148]
\frac{500miles}{trip}\times6trips=3000miles
\frac{300miles}{\frac{11miles}{minute}}=272.72minue\approx4.54hrs
4 0
3 years ago
Find the value of x and y
Zolol [24]
2x=9-y
3y=x-8

y=9-2x
3(9-2x)=x-8

27-6x=x-8
35=7x
x=5

2*5=9-y
10=9-y
y-1
7 0
3 years ago
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