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2 years ago

Need answer asap 2r+3s-t=3 solve for r,s,and t

Mathematics

2 answers:

Ahat [919]2 years ago

7 0

Answer:

t=2

Step-by-step explanation:

this is the t answer k

bogdanovich [222]2 years ago

6 0

Answer:

Use Photo math. It will explain the steps.

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P P,Q and R can finish a task in 8, 10 and 12 hours respectivly.They started working together but after 3 hours, P and R left. H

zimovet [89]

Answer:

45 minutes

Step-by-step explanation:

Assume task completed in total x hours

$\frac{x}{10} + \frac{3}{8} + \frac{3}{12} = 1 \\ 12x + 45 + 30 = 120 \\ 12x = 45 \\ x = \frac{15}{4} = 3 \frac{3}{4}$

So q will take 45 more minutes

7 0

2 years ago

Given the following observed and expected data (total of 1000), using chi-squared calculate a p-value that corresponds with this

finlep [7]

Answer:

The answer is " $0.90>p>0.75.$ "

Step-by-step explanation:

$\text{Cinnabar vestigial} \ \ \ \ \ \ \ \ \ \ \ 384 \ \ \ \ \ \ \ \ \ \ \ 390 \ \ \ \ \ \ \ \ \ \ \ -6 36 \ \ \ \ \ \ \ \ \ \ \ 0.092308\\\\$

$roof \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 408 \ \ \ \ \ \ \ \ \ \ \ 390 \ \ \ \ \ \ \ \ \ \ \ 18 \ \ \ \ \ \ \ \ \ \ \ 324 \ \ \ \ \ \ \ \ \ \ \ 0.830769\\\\\text{Cinnabar vestigial roof} \ \ \ \ \ \ \ \ \ \ \ \ \ 63 \ \ \ \ \ \ \ \ \ \ \ \ \ 70\ \ \ \ \ \ \ \ \ \ \ \ -7 \ \ \ \ \ \ \ \ \ \ \ 49 \ \ \ \ \ \ \ \ \ \ \ 0.7\\\\\text{wild type} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 72 \ \ \ \ \ \ \ \ \ \ \ 70 \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ 0.057143\\\\$

$vestigial \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 32 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 35 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.257143\\\\$

$\text{Cinnabar roof} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 34\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 35 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.028571\\\\\text{roof vestigial} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ -1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.2\\\\$

$\text{cinnabar} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.8 \\\\$

$Total \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1000 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2.965934$

Eight phenotypes were present.

Df is provided also by a number of phenotypes -1 The degree of freedom

$\to df = 8-1= 7$

For p-value 0,9, Chi-square is 2.83;

The p-value of 0.75 is 4.5. Chi-square

Chi-sqaure value is observed at 2.965.

That means 0.90>p-value>0.75.

7 0

2 years ago

A football is selling for $35 off the original price. The original price was $60. What is the sale price of the football?

Strike441 [17]

All you have to do it do 60 - 35 = 25 dollars because they want to know if the original price would be 60 dollars and they wanna know the anwser if you took away 35 dollars. so then you just subtract

5 0

3 years ago

"Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through

Stella [2.4K]

Answer:

it is not necessary to confirm that the sample data appear to be from a population with a normal distribution;

D. Because the sample size of 50 is greater than 30, it can be assumed that the sample mean is from a population with a normal distribution

Step-by-step explanation:

Normal distribution which is otherwise known as the Gaussian distribution, it is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean.

The arithmetic mean or average; is the sum of a collection of numbers divided by the total numbers in the collection.

6 0

3 years ago

What is the perimeter of the quadrilateral shown below?

GarryVolchara [31]

The perimeter of a shape is the sum of the lengths of its sides.

So, to find the perimeter of this quadrilateral, all we have to do is add the side lengths and simplify.

(x² - 6) + (2x + 5) + (x² - 3x) + (4x² + 2x)

x² + x² + 4x² + (-3x) + 2x + 2x + (-6) + 5

6x² + (-3x) + 2x + 2x + (-6) + 5

6x² + x + (-6) + 5

6x² + x + (-1)

6x² + x - 1

So, the perimeter of the quadrilateral is the quantity (6x² + x - 1).

Hope this helps!

8 0

2 years ago