Two cuboid-shaped metal bars are the same size. They are 12.4 cm long, 5.6 cm wide and 2.5 cm thick.
1 answer:
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Answer:
(a)2(89x+84)
(b)
Step-by-step explanation:
The dimensions of the larger rectangular field are:
- Length=5x + 12; Width = 9x + 14.
The dimensions of the smaller rectangular soccer field are:
- Length=5x; Width = 9x.
(a)Area of the part of the field that is outside the soccer field
=Area of the larger rectangular field - Area of the Soccer Field
=(5x+12)(9x+14)-5x(9x)
=(5x)(9x)+70x+108x+168-5x(9x)
=178x+168
=2(89x+84)
(b)Radius of the Semicircular Fountain =2x
From Part (a),
Area of the larger rectangular field - Area of the Soccer Field=178x+168
Area of the Semicircular Fountain =
Area of the Field that does not include the soccer field or the fountain.
=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain