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3 years ago

Two cuboid-shaped metal bars are the same size. They are 12.4 cm long, 5.6 cm wide and 2.5 cm thick.

Mathematics

1 answer:

nordsb [41]3 years ago

8 0

Answer:

191 grams

Step-by-step explanation:

12.4×5.6×2.5=173.6

7.9×173.6=1371.44

9.0×173.6=1562.4

1562.4-1371.44=191

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Can someone help me again pleaseeee :')

GenaCL600 [577]

The answer is I because S is at -2 and T is at 4.

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3 years ago

WHAT THE HECK IS THE ANSWER TO THIS -(3x+y)+2(x-4y)

Gnom [1K]

Answer:

-x -9y

Step-by-step explanation:

-(3x+y)+2(x-4y)

-3x -y +2x -2*4y

-x -y -8y

-x -9y

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3 years ago

Read 2 more answers

Akira is folding a piece of paper that is 0.2 millimeters thick in half. The thickness of the paper doubles with each fold. Let

Ostrovityanka [42]

Answer:

t(n)= 0.2 * 2ⁿ

Step-by-step explanation:

Thickness= 0.2 millimeters

paper = 1

n= number of folds

The exponential function will be given by

t(n)= 0.2 * 2ⁿ

so if there's a single fold

t(1)= 0.2 * 2¹

t(1)= 0.4 mm

Now for 2 folds the thickness will be

t(2) = 0.2 *2 ²

t(2)= 0.2 *4

t(2) = 0.8mm

The exponential that represents this scenario is

t(n)= 0.2 * 2ⁿ

And for 3 folds the thickness will be

t(3) = 0.2 *2 ³

t(3)= 0.2 *8

t(3) = 1.6 mm

4 0

3 years ago

Find the are of the shape below

skelet666 [1.2K]

Answer:

Area is 235

Step-by-step explanation:

Split the shape evenly so 11 x 14 and 9 x 9then multly and add

when slpitting up the number some times you have to add or subtract so to get 9 x 9 we just take 20 then take away 11 due to the line going through 20 and 20 - 11 = 9

9 x 9 = 81

11 x 14 = 154

81 + 154 = 235

Simular to the first one but the cutting line is different. this time the line cuts through 14

9 x 20 = 180

11 x 5 = 55

180 + 55 = 235

8 0

2 years ago

Meth Barie's ice cream shop wants to decide whether to introduce a new ice cream flavor. They randomly selected 15 customers at

Marianna [84]

Answer:

Meth Barie's ice cream shop should not introduce the new ice cream flavor.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 4.01

Sample mean, $\bar{x}$ = 4.4

Sample size, n = 15

Alpha, α = 0.1

Sample standard deviation, s = 1.6 minutes

First, we design the null and the alternate hypothesis

$H_{0}: \mu \leq 4.01\\H_A: \mu > 4.01$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{4.4 - 4.0}{\frac{1.6}{\sqrt{15}} } = 0.968$

Option B) 0.968

Rejection region:

Now, $t_{critical} \text{ at 0.10 level of significance, 9 degree of freedom } = 1.345$

So the rejection region would be a value of t-statistic greater than 1.345.

Option B) t > 1.345

Conclusion:

Since,

$t_{stat} < t_{critical}$

We fail to reject the null hypothesis and accept the null hypothesis. Meth Barie's ice cream shop should not introduce the new ice cream flavor.

8 0

3 years ago