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3 years ago

Two cuboid-shaped metal bars are the same size. They are 12.4 cm long, 5.6 cm wide and 2.5 cm thick.

Mathematics

1 answer:

nordsb [41]3 years ago

8 0

Answer:

191 grams

Step-by-step explanation:

12.4×5.6×2.5=173.6

7.9×173.6=1371.44

9.0×173.6=1562.4

1562.4-1371.44=191

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hi so im really desperate because this is due in exactly 6 minutes and people wont answer without scamming me and these are sum

AfilCa [17]

Answer:

1. 7

2. 1.25, 5/4, 1 1/4

3. -0.7

4. 20

5. 4.8

6. 30

7. 1.4

8. 28

9. -3.3 (the last 3 is infinite)

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3 years ago

vik wrote the equation 470 h equals 3,008 where h is the number of hours it took a plane flying at a constant speed of 470 miles

Hunter-Best [27]

As with any linear equation of this sort, divide by the coefficient of the variable.
.. 470 h = 3008
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4 0

3 years ago

A swimming pool is a shape of a right rectangular prism if the pool is 12 3/4 yards long 5 2/3 yards wide and 9 yards deep what

Artemon [7]

Answer:

$V=650.25\ yards^3$

Step-by-step explanation:

Given that,

Length = $12\dfrac{3}{4}\ yards$

Width = $5\dfrac{2}{3}\ yards$

Depth = 9 yards

We need to find the volume of the swimming pool. The formula for the volume of a cuboid shape is given by :

$V=lbh\\\\V=12\dfrac{3}{4}\times 5\dfrac{2}{3}\times 9\\\\=\dfrac{51}{4}\times \dfrac{17}{3}\times 9\\\\V=650.25\ yards^3$

So, the volume of the swimming pool is equal to $650.25\ yards^3$ .

7 0

3 years ago

Select the correct product. (x + 8)(y + 3) xy + 8x + 3y + 24 xy + 3x + 8y + 24 11xy 24xy

MAXImum [283]

(x + 8)(y + 3)

x*(y+3) + 8*(y + 3)

x*y + 3*x + 8*y + 3*8

xy + 3x + 8y + 24

So the correct product is = xy + 3x + 8y + 24, I guess the second expression.

I hope this helps.

4 0

3 years ago

Read 2 more answers

Call an integer $n$ oddly powerful if there exist positive integers $a$ and $b$, where $b>1$, $b$ is odd, and $a^b = n$. How

azamat

Answer:

There are 16 oddly powerful integers less than 2010

Step-by-step explanation:

∵ b is an odd integer

∵ b > 1

∴ The first value of b is 3

∵ a is an integer

- We can use a = 1, 2, 3, ..........

∵ $a^{b}=n$

∵ n < 2010

- Let a = 1, 2, ............... 12 because 12³ is greatest integer < 2010

∵ 1³ = 1, 2³ = 8, 3³ = 27, 4³ = 64, 5³ = 125, 6³ = 216, 7³ = 343,

8³ = 512, 9³ = 729, 10³ = 1000, 11³ = 1331, 12³ = 1728

∴ There are 12 oddly powerful integers with b = 3

Now the second value of b is 5

$1^{5}=1$ but we took 1 before so we will start with 2

∵ $2^{5}=32$ , $3^{5}=243$ , $4^{5}=1024$

- $4^{5}$ is the greatest integer < 2010

∴ There are 3 oddly powerful integers with b = 5

Now the third value of b is 7

∵ $2^{7}=128$

- $2^{7}$ is the greatest integer < 2010

∴ There is 1 oddly powerful integers with b = 7

Now the fourth value of b is 9

∵ $2^{9}=512$

- $2^{9}$ is the greatest integer < 2010

- But we used 512 before

∴ There is no oddly powerful integers with b = 9

- 9 is the greatest value of b which makes $a^{b}$

∵ 12 + 3 + 1 = 16

∴ There are 16 oddly powerful integers less than 2010

5 0

3 years ago