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jeka94
3 years ago
15

The time is takes to drive between two cities varies inversely

Mathematics
1 answer:
zmey [24]3 years ago
8 0

Answer:

3.5 hour driving at 65 miles per hour

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A housepainter mixed 2 gallons of blue paint with
maria [59]

Answer:

Option D: 6:12 is correct answer.

Step-by-step explanation:

We can find the simplest form of ratio to compare it with the given ratios.

According to given statement,

The ratio is:

No.\ of\ Blue\ Paint\ Gallons: No.\ of\ red\ paint\ gallons\\2:4\\Simplifying\\1:2

Now we will check if the given options can be simplified to 1:2

So,

Option A:

8:12\\2:3

Option B:

8:24\\1:3

Option C:

3:5

Option D:

6:12\\1:2

As we can see that 6:12 can be simplified to 1:2 which is same as 2:4 so it will make the same shade of purple.

Hence,

Option D: 6:12 is correct answer.

8 0
3 years ago
3x/2 - x = x/10 - 6/5
SVETLANKA909090 [29]

Answer:  -3

X  =  -3        

Step-by-step explanation:

Multiply the numbers i hope this helps god bless

8 0
3 years ago
Read 2 more answers
Ronald saves 10.00 to buy a new book. The book original price was 15 but it was on sale for 35% off with a 6% sales tax. Does he
Lady bird [3.3K]
$6.89

The book is $10. Minus the 35% discount ($10X0.35=$3.50). So the subtotal is $10-$3.50=$6.50.

Tax is 6%. So 0.06X$6.50=$0.39

The total including tax is $6.50+$0.39=$6.89
3 0
2 years ago
In the adjoining figure , APB and AQC are equilateral triangles. Prove that PC = BQ. ( Hint : <img src="https://tex.z-dn.net/?f=
just olya [345]

Answer:

See Below.

Step-by-step explanation:

Statements:                                                           Reasons:

\displaystyle 1)\text{ } \Delta APB \text{ and } \Delta AQC \text{ are equilateral triangles}      Given

\displaystyle 2) \text{ } m \angle PAB = 60                                                     Definition of equilateral.

3)\text{ } m \angle QAC = 60                                                     Definition of equilateral.

4)\text{ } m\angle PAB = m\angle QAC                                          Substitution

5)\text{ } m\angle PAC=m\angle PAB+m\angle BAC                       Angle Addition

\displaystyle 6)\text{ } m\angle QAB=m\angle QAC+m\angle BAC                       Angle Addition

7)\text{ } m\angle QAB=m\angle PAB+m\angle BAC                       Substitution

\displaystyle 8)\text{ } m\angle PAC=m\angle QAB                                         Substitution

9)\text{ } PA=BA                                                          Definition of equilateral

10)\text{ } AC=AQ                                                        Definition of equilateral

\displaystyle 11)\text{ } \Delta PAC \cong \Delta BAQ                                            Side-Angle-Side Congruence*

\displaystyle 12)\text{ } PC=BQ                                                        CPCTC

* SAS Congruence:

PA = BA

∠PAC = ∠QAB

AC = AQ

6 0
2 years ago
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