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kotegsom [21]
3 years ago
9

WILL MARK BRAINLIEST!!!! please help, show work if you can

Mathematics
1 answer:
enyata [817]3 years ago
4 0

Answer:

(2x+5) (3x-7)

Step-by-step explanation:

(2x+5) (3x-7) is correct cause you multiply the two sides to get the answer

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Sally painted a picture that has an area of 480 square inches. The length of the painting is 1 1/5 as long as it is wide. What a
marishachu [46]
So Length * Width = 480 in. sq.
L=1 1/5 or 1.2W
substitute the L for 1.2W
1.2W*W=480 in sq
divide both sides by 1.2
w*w= 400
W²=400
square root of both sides
Width = 20 inches
Length= (1.2width) or (20*1.2)
Length=24 inches
6 0
3 years ago
Help me I need help I need help
Licemer1 [7]

Answer:

\Huge\boxed{131.88}

Step-by-step explanation:

Hello There!

First thing we want to do is find the formula for circumference of a circle

C = 2(3.14)r

where r = radius

we are given the diameter so we have to convert that into radius to do so we just divide by 2

42/2=21 so the radius equals 21 inches

now we just plug in 21 for r in the formula

C = 2(3.14)21\\2*3.14=6.28\\6.28*21=131.88\\C=131.88

So we can conclude that the circumference of the circle is 131.88 inches

3 0
3 years ago
how many minutes is it before 12 noon if 20 minutes ago it was three times as many minutes after 9 am
Hunter-Best [27]
First, change everything into minutes.
12 noon is 12 by 60 which = 720 minutes.
9am is 9 by 12 which = 540 minutes.
X is now your number of minutes before noon.So noon - x is the next step:
720 - x
20 minutes ago it was 720 - x - 20
720 - x - 20= 540 + 3x (3x because you're looking for 3 times as many minutes)
720 - 20 - 540=4x (you combine all the like numbers and variables) 
160 = 4x
160/4= x
40 = x
Your answer is 40 minutes
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7 0
3 years ago
A and B are points on a line that has the slope 2. The abscissa of B exceeds the abscissa of A by 3.5. State the relationship of
Troyanec [42]

Answer:

The ordinate of B exceeds the ordinate of A by 7

Step-by-step explanation:

Let

A(x1,y1),B(x2,y2)

where

x1 is the abscissa of A

x2 is the abscissa of B

y1 is the ordinate of A

y2 is the ordinate of B

we know that

m=\frac{y2-y1}{x2-x1}

m=2

so

2=\frac{y2-y1}{x2-x1}  -----> equation A

x2=x1+3.5 ----> equation B

substitute equation B in equation A

2=\frac{y2-y1}{x1+3.5-x1}  

2=\frac{y2-y1}{3.5}  

7=y2-y1  

y2=y1+7  

therefore

The ordinate of B exceeds the ordinate of A by 7

6 0
3 years ago
Suppose m = 2 + 6i, and | m + n | = 3√10, where n is a complex number.
Ksju [112]

Answer: a) √50

b) n = 1 + 7i

Step-by-step explanation:

first, the modulus of a complex number z = a + bi is

IzI = √(a^2 + b^2)  

The fact that n is complex does not mean that n doesn't has a real part, so we must write our numbers as:

m = 2 + 6i

n = a  + bi

Im + nI = 3√10

Im + n I = √(a^2 + b^2 + 2^2 + 6^2)= 3√10

            = √(a^2 + b^2 + 40) = 3√10

             a^2 + b^2 + 40 = 3^2*10 = 9*10 = 90

             a^2 + b^2 = 90 - 40 = 50

            √(a^2 + b^2 ) = InI = √50

The modulus of n must be equal to the square root of 50.

now we can find any values a and b such a^2 + b^2 = 50.

for example, a = 1 and b = 7

1^2 + 7^2 = 1 + 49  = 50

Then a possible value for n is:

n = 1 + 7i

6 0
3 years ago
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