Answer:
n= 11.65 years
Step-by-step explanation:
Giving the following information:
Present Value (PV)= $33,000
Future Value (FV)= $15,000
Decrease rate (d)= 7%
<u>To calculate the number of years it will take to reach $15,000; we need to use the following formula:</u>
<u></u>
n= ln(FV/PV) / ln(1+d)
n= ln(15,000/33,000) / ln(1.07)
n= 11.65 years
Using the Law of Sines (sinA/a=sinB/b=sinC/c) and the fact that all triangles have a sum of 180° for their angles.
The third angle is C is 180-53-17=110°
27/sin53=b/sin17=c/sin110
b=27sin17/sin53, c=27sin110/sin53
And the perimeter is a+b+c so
p=27+27sin17/sin53+27sin110/sin53 units
p≈68.65 units (to nearest hundredth of a unit)
Answer: 0.6065
Step-by-step explanation:
Given : The machine's output is normally distributed with
![\mu=27\text{ ounces per cup}](https://tex.z-dn.net/?f=%5Cmu%3D27%5Ctext%7B%20ounces%20per%20cup%7D)
![\sigma=3\text{ ounces per cup}](https://tex.z-dn.net/?f=%5Csigma%3D3%5Ctext%7B%20ounces%20per%20cup%7D)
Let x be the random variable that represents the output of machine .
z-score : ![z=\dfrac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
For x= 21 ounces
![z=\dfrac{21-27}{3}\approx-2](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B21-27%7D%7B3%7D%5Capprox-2)
For x= 28 ounces
![z=\dfrac{28-27}{3}\approx0.33](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B28-27%7D%7B3%7D%5Capprox0.33)
Using the standard normal distribution table , we have
The p-value : ![P(21](https://tex.z-dn.net/?f=P%2821%3Cx%3C28%29%3DP%28-2%3Cz%3C0.33%29)
![P(z](https://tex.z-dn.net/?f=P%28z%3C0.33%29-P%28z%3C-2%29%3D0.6293-0.0227501%3D0.6065499%5Capprox0.6065)
Hence, the probability of filling a cup between 21 and 28 ounces= 0.6065
Your answer is 104 square inches because you have to find the area of the top rectangle by multiplying 12 x 7, then find the area of the bottom square by multiplying 5 x 4, and then add both answers together which equals 104 square centimeters ;)
Step-by-step explanation:
the formula of coordinates (x, y) that reflected across the x-axis : (x, y) => (x, -y)
so,
A(3, -2) => A'(3, 2)
B(5, 5) => B'(5, -5)
C(-4, 2) => C'(-4, -2)