Answer:
I hope it helps u
Step-by-step explanation:
Let's solve your system by elimination.
15j+12k=18;5j+4k=6
Multiply the second equation by -3, then add the equations together.
(15j+12k=18)
−3(5j+4k=6)
Becomes:
15j+12k=18
−15j−12k=−18
Add these equations to eliminate j:
0=0
Answer:
Infinitely many solutions
Note: Please Brain-list it ok dear!
If u have any doubt you can ask ok
Answer:
0
Step-by-step explanation:
given that we roll a fair die repeatedly until we see the number four appear and then we stop.
the number 4 can appear either in I throw, or II throw or .... indefinitely
So X = the no of throws can be from 1 to infinity
This is a discrete distribution countable.
Sample space= {1,2,.....}
b) Prob ( 4 never appears) = Prob (any other number appears in all throws)
= 
where n is the number of throws
As n tends to infinity, this becomes 0 because 5/6 is less than 1.
Hence this probability is approximately 0
Or definitely 4 will appear atleast once.
The volume of the original cylinder is
... V = π·r²·h
For r=1 and h=1, this is
... V = π·1²·1 = π
For the new cylinder, the volume is 1.089 times that amount.
... V = 1.089π = π·1.1²·(1-k)
... 1.089/1.21 = 1-k
... k = 1 - 1.089/1.21 = 1 - 0.9 = 0.1 = 10%
The appropriate choice is (B) 10.
<span>0.583333333 feet
If I helped, press "Thanks" button. It will make me happy</span>
Answer:
2^52
Step-by-step explanation:
(8^-5/2^-2)^-4 = (2^-15/2^-2)^-4= (2^-13)^-4= 2^((-13*(-4))= 2^52
