Answer:
Parallel line:

Perpendicular line:

Step-by-step explanation:
we are given equation 4x+5y=19
Firstly, we will solve for y

we can change it into y=mx+b form


so,

Parallel line:
we know that slope of two parallel lines are always same
so,

Let's assume parallel line passes through (1,1)
now, we can find equation of line

we can plug values

now, we can solve for y

Perpendicular line:
we know that slope of perpendicular line is -1/m
so, we get slope as

Let's assume perpendicular line passes through (2,2)
now, we can find equation of line

we can plug values

now, we can solve for y

Answer:
280
Step-by-step explanation:
<u><em>The question in English is</em></u>
Write the number that has the same value as 28 tens
we know that
One tens is equal to the number 10
so
To find out the value of 28 tens, multiply the number 28 by 10

Answer:
A) p = 2x - 4 for the expression. B) Your team scored 44 points.
Step-by-step explanation:
Let <u>P</u> represent the points your team made.
Since the question says "Your basketball team scored 4 fewer than twice as many points as the other team." this is how I came up with the expression.
p = 2x - 4 ( our points = 2 times more then the other teams points minus 4.
Using this expression and the given information that the other team made 24 points, I solved B.
44 = 2(24) - 4.
Answer:its citc (C)
Step-by-step explanation:
Answer:

Step-by-step explanation:
The general form of a quadratic polynomial is given by:
(1)
You have the following polynomial:
(2)
In order to complete the factorization you can use the quadratic formula, to obtain the roost of the polynomial. The quadratic formula is given by:
(3)
By comparing the equation (1) with the equation (2) you obtain:
a = 3
b = -10
c = 8
Then, you replace these values in the equation (3):

Then, the factorization of the polynomial is:
