Answer:
okay
Step-by-step explanation:
N is the variable I believe.
Step-by-step explanation:
Since PT = 2PM and AR = 2AD,
The midsegment MD must be the average of PA and TR:
Therefore we have
2(20x + 4) = 10 + (34x + 16)
=> 40x + 8 = 34x + 26
=> 6x = 18
=> x = 3
Hence length of MD
= 40(3) + 8 = 128.
For the answer to the question above,
<span>a) Use F = k * q1 * q2 / d²
where k = 8.99e9 N·m²/C²
and q1 = -1.602e-19 C (electron)
and q2 = 1.602e-19 C (proton)
and d = distance between point charges = 0.53e-10 m
The negative result indicates "attraction".
b) Here, just use F = ma
where F was found above, and
m = mass of electron = 9.11e-31kg, if memory serves
a = radial acceleration
c) Now use a = v² / r
where a was found above
and r was given
d) period T = 2π / ω = 2πr / v
where v was found above
and r was given </span>
