Question

The area of a rectangle is 99 ft^2, and the length of the rectangle is 7 more than double the width. Find the dimensions of the rectangle.

Answer 1

Answer:

width =5.5ft

length =18

Step-by-step explanation:

w=x

L=2x+7

area=w*L

99 = x(2x+7)

$99=2x^{2} +7x$

$2x^{2} +7x-99=0$

$2x^{2} +18x-11x-99=0$

2x(x+9)-11(x+9)=0

(2x-11)(x+9)=0

2x-11=0

2x=11

x=11/2

x=5.5

L=2x+7=2*5.5+7=11+7=18