The third choice is appropriate.
an = 5 - 3(n - 1); all integers n ≥ 1
_____
This equation follows the form for the general term of an arithmetic sequence.
an = a1 + d(n - 1)
where a1 is the first term (corresponding to n=1), and d is the common difference. From the problem statement, a1 = 5 and d = 2 - 5 = -3.
Answer:
The value of annuity is 
Step-by-step explanation:
From the question we are told that
The periodic payment is 
The interest rate is 
Frequency at which it occurs in a year is n = 4 (quarterly )
The number of years is 
The value of the annuity is mathematically represented as
![P_v = P * [1 - (1 + \frac{r}{n} )^{-t * n} ] * [\frac{(1 + \frac{r}{n} )}{ \frac{r}{n} } ]](https://tex.z-dn.net/?f=P_v%20%20%3D%20%20P%20%2A%20%20%5B1%20%20-%20%281%20%2B%20%5Cfrac%7Br%7D%7Bn%7D%20%29%5E%7B-t%20%2A%20n%7D%20%5D%20%2A%20%5B%5Cfrac%7B%281%20%2B%20%5Cfrac%7Br%7D%7Bn%7D%20%29%7D%7B%20%5Cfrac%7Br%7D%7Bn%7D%20%7D%20%5D)
(reference EDUCBA website)
substituting values
![P_v = 250 * [1 - (1 + \frac{0.05}{4} )^{-10 * 4} ] * [\frac{(1 + \frac{0.05}{4} )}{ \frac{0.08}{4} } ]](https://tex.z-dn.net/?f=P_v%20%20%3D%20250%20%2A%20%20%5B1%20%20-%20%281%20%2B%20%5Cfrac%7B0.05%7D%7B4%7D%20%29%5E%7B-10%20%2A%204%7D%20%5D%20%2A%20%5B%5Cfrac%7B%281%20%2B%20%5Cfrac%7B0.05%7D%7B4%7D%20%29%7D%7B%20%5Cfrac%7B0.08%7D%7B4%7D%20%7D%20%5D)
![P_v = 250 * [1 - (1.0125 )^{-40} ] * [\frac{(1.0125 )}{0.0125} ]](https://tex.z-dn.net/?f=P_v%20%20%3D%20%20250%20%2A%20%20%5B1%20%20-%20%281.0125%20%29%5E%7B-40%7D%20%5D%20%2A%20%5B%5Cfrac%7B%281.0125%20%29%7D%7B0.0125%7D%20%5D)
![P_v = 250 * [0.3916 ] * [\frac{(1.0125)}{0.0125} ]](https://tex.z-dn.net/?f=P_v%20%20%3D%20%20250%20%2A%20%20%5B0.3916%20%5D%20%2A%20%5B%5Cfrac%7B%281.0125%29%7D%7B0.0125%7D%20%5D)
Answer:
True ( A )
Step-by-step explanation:
4 ( 5 ) - 2 = 2 ( 5 ) + 8
20 - 2 = 10 + 8
18 = 18
This is a correct statement because 18 does equal 18
<span>A relationship that occurs when variable quantities are directly proportional to one another. A linear relationship can be represented on a graph as a straight line.
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