Answer:
Percent of error of Logan's Estimate is 12.5%
Step-by-step explanation:
Given:
Actual Volume of sample =48 mL
Estimated Volume of sample = 42 mL
We need to find the percent errors of Logan estimate.
To calculate percent of error below are the steps.
Step 1: Subtract the Actual value from the estimated value.
Step 2: Take the absolute value of step 1
Step 3: Divide that answer by the Actual value.
Step 4: Multiply that answer by 100 and add the % symbol to express the answer as a percentage.
Now Substituting the values we get;
Step 1: To Subtract Actual Volume with Estimated Volume
Estimated Volume of sample - Actual Volume of sample = 42 - 48 = -6 mL
Step 2: Find Absolute value we get;
![|-6| = 6](https://tex.z-dn.net/?f=%7C-6%7C%20%3D%206)
Step 3 : Divide that answer by the Actual volume.
![\frac{6}{48}=0.125](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B48%7D%3D0.125)
Step 4: Multiply that answer by 100 and add the % symbol to express the answer as a percentage.
![0.125\times 100 = 12.5\%](https://tex.z-dn.net/?f=0.125%5Ctimes%20100%20%3D%2012.5%5C%25)
Hence Percent of error of Logan's Estimate is 12.5%