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3 years ago

Determine the mean absolute deviation 8, 0, 4, 7, 4, 5, 3, 3

Mathematics

1 answer:

velikii [3]3 years ago

5 0

Answer:

I would say it's 4 or 7.

Step-by-step explanation:

its wrong i just know it is :(

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Help please !! easy question i believe :))

kolezko [41]

Solve for x given two sides

Solution

x is an angle hence we are gonna use the formula Sin

Sin 0 = opp/hyp

0 represents theta.

Sin 0 = opp/hyp
Sin 0 = 27/33

Put 27/33 in decimal form

= 0.8181

Transpose to make 0 the subject

Sin 0 = 0.8181

0 = Sin-1 0.8181

When adding Sin from one side to another it becomes Sin inverse.

0 = Sin-1 08181

Now we find the answer

0 = Sin-1 0.8181

= 54.89 degrees

Therefore x is equal to 54.9 to the nearest tenth.

6 0

3 years ago

Express this equation in logarithmic form. y = 10^x x = ?

Lana71 [14]

From definition we have:

$$x=\log_{10}y$

8 0

3 years ago

What is the third quartile of this data set? 20, 21, 24, 25, 28, 29, 35, 37, 42

nata0808 [166]

Answer:

Step-by-step explanation:

⇒The question is on third quartile

⇒To find the third quartile we calculate the median of the upper half of the data

Arrange the data in an increasing order

20, 21, 24, 25, 28, 29, 35, 37, 42

Locate the median, the center value

20, 21, 24, 25, 28, 29, 35, 37, 42

The values 20, 21, 24, 25 ------------lower half used in finding first quartile Q1

The value 28 is the median

The vlaues 29, 35, 37, 42...............upper half used in finding 3rd quartile Q3

Finding third quartile Q3= median of the upper half

upper half= 29,35,37,42

median =( 35+37)/2 = 36

6 0

3 years ago

A random sample of 85 group leaders, supervisors, and similar personnel at General Motors revealed that, on average, they spent

andreyandreev [35.5K]

Answer:

Step-by-step explanation:

From the information given,

Number of personnel sampled, n = 85

Mean or average = 6.5

Standard deviation of the sample = 1.7

We want to determine the confidence interval for the mean number of years that personnel spent in a particular job before being promoted.

For a 95% confidence interval, the confidence level is 1.96. This is the z value and it is determined from the normal distribution table. We will apply the following formula to determine the confidence interval.

z×standard deviation/√n

= 1.96 × 6.5/√85

= 1.38

The confidence interval for the mean number of years spent before promotion is

The lower end of the interval is 6.5 - 1.38 = 5.12 years

The upper end is 6.5 + 1.38 = 7.88 years

Therefore, with 95% confidence interval, the mean number of years spent before being promoted is between 5.12 years and 7.88 years

4 0

3 years ago

The product of x and the sum of 6 and 8 times the square of x

tensa zangetsu [6.8K]

Answer:

x = 14; x = 0

Step-by-step explanation:

(x)(6 + 8) = x²

(x)(14) = x²

14x = x²

14x - x² = 0

(x)(14 - x) = 0

x = 14; x = 0

8 0

3 years ago