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NeTakaya
3 years ago
10

How do you solve problems like 6.45/0.25

Mathematics
2 answers:
Kobotan [32]3 years ago
6 0

Answer:

25.8

Step-by-step explanation:

divide

klio [65]3 years ago
6 0

Answer:

divide like i said

Step-by-step explanation:

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Please answer question plz!!!!!
Neporo4naja [7]

Answer:

V = 214.32

Step-by-step explanation:

Remark

You have to be a little careful with this question. The temptation is just to take the difference of the heights. That is not correct. The difference has to be multiplied by the base to get the volume.

Formula

V = (h1 - h2)* Base

Givens

h1 = 32.9

h2 = 29.1

Base = 56.4

Solution

V = 56.4 ( 32.9 - 29.2)

V = 56.4 * 3.8

V = 214.32

6 0
3 years ago
40 divided [24-4 x (2+3)]
777dan777 [17]
\frac{40}{24 - 4 * (2 + 3)} =\ \textgreater \ 
 \frac{40}{20 * (5)} =\ \textgreater \ 
 \frac{40}{100}

Final answer .40
3 0
3 years ago
Eddie needs 2 2/3 cups of flour for one batch of pancakes. How much flour does he need for 2 1/2 batches?
Alexxandr [17]

for 1 batch of pancake = 2 2/3 = 8/3 cups

for 2 1/2 = 5/2 pancake = 8/3 * 5/2 = 40/6 cups = 6 4/6 cups

7 0
3 years ago
Read 2 more answers
Which number line represtents the solution to |x+4|=2?​
vlada-n [284]

Answer:

Points -2 and -6 on the number line are the two solutions.

Step-by-step explanation:

Use the definition of absolute value as a starting point

|x|=x\,\,\mbox{for}\,\,x\geq 0\\|x|=-x\,\,\mbox{for}\,\,x

To solve the equation, you need to treat the two cases as above:

|x+4|=x+4=2\,\,\,\mbox{for}\,\,x+4\geq 0\implies x\geq -4\\x+4=2\implies x=-2

The solution x=-2 is consistent with the condition x>=-4, so it is the first and valid solution. Now the second case of the absolute value:

|x+4|=-(x+4)=2\,\,\,\mbox{for}\,\,x+4< 0\implies x

Again, the second solution -6 complies with the requirement that x<-4, so it is valid.

7 0
3 years ago
1. Find the value of
spin [16.1K]

9514 1404 393

Answer:

  1. -√5
  2. 3/5
  3. -4/5

Step-by-step explanation:

The relevant relations are ...

  sec = ±√(tan² +1)

  cos = 1/sec

  csc = 1/sin = ±1/√(1 -cos²)

Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.

__

1. sec(θ) = -√((-2)² +1) = -√5

2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5

3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5

8 0
3 years ago
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