Answer:
x = 5√2
y = 5√6
z = 5√3
ΔABC ~ ΔBDC ~ ΔADB
Step-by-step explanation:
ΔABC, ΔBDC, and ΔADB are all similar triangles to each other.
By definition of similar triangles, the corresponding sides have the same ratios.
CD from ΔBDC corresponds to BD from ΔADB, and BD from ΔBDC corresponds to AD from ΔADB. So:
CD / BD = BD / AD
10 / x = x / 5
x² = 50
x = 5√2
Since ΔBDC is right, we can use the Pythagorean Theorem to solve for y:
CD² + BD² = BC²
10² + (5√2)² = y²
y² = 100 + 50 = 150
y = 5√6
Again, since ΔΔABD is right, we can use the Pythagorean Theorem to solve for z:
AD² + BD² = AB²
5² + (5√2)² = z²
z² = 25 + 50 = 75
z = 5√3
W + 3w = 90 is obviously wrong
Answer:
See below ~
Step-by-step explanation:
<u>Question 1</u>
⇒ -7x - (8x + 16) = -1
⇒ -7x - 8x - 16 = -1
⇒ -15x = 15
⇒ x = -1
⇒ y = 8(-1) + 16 = 8
⇒ Solution = <u>(-1, 8)</u>
<u></u>
<u>Question 2</u>
⇒ 3x + 4(-3x - 18) = 0
⇒ 3x - 12x - 72 = 0
⇒ -9x = 72
⇒ x = -8
⇒ y = -3(-8) - 18 = 6
⇒ Solution = <u>(-8, 6)</u>
<u>Question 3</u> (not clear)
<u>Question 4</u>
⇒ -8x - 7(6x) = 0
⇒ -8x - 42x = 0
⇒ -50x = 0
⇒ x = 0
⇒ y = 6(0) = 0
⇒ Solution = <u>(0, 0)</u>
<u>Question 8</u>
- 2x - 6y = -14
- y = -5x - 19
⇒ 2x - 6(-5x - 19) = -14
⇒ 2x + 30x + 114 = -14
⇒ 32x = -128
⇒ x = -4
⇒ y = -5(-4) - 19 = 1
⇒ Solution = <u>(-4, 1)</u>
I think the answer would be 4 and the reason why is because
Answer: The p(success) = 0.6
Your question is a little unclear, but I believe you are asking about the probability that at least one of the trials in the experiment were successful.
If that is the case, you simply have to add the probability of 1 success with the probability of 2 successes.
That is 0.48 + 0.16 = 0.64
Rounding our answer to one decimal place gives us 0.6.
