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2 years ago

It took a car 4 hours to travel 180 miles. If the car drove a steady speed, how fast was it going?

Mathematics

1 answer:

tester [92]2 years ago

7 0

Answer:

45 mph

Step-by-step explanation:

It took the car 4 hours to travel 180 miles

Then

It took the car 4/4 hours to travel 180/4 miles

Since 4/4 = 1 and 180/4 = 45

Then

It took the car 1 hours to travel 45 miles

Therefore ,the car was it going at 45 mph

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We have n = 100 many random variables Xi ’s, where the Xi ’s are independent and identically distributed Bernoulli random variab

777dan777 [17]

Answer:

(a) The distribution of $X=\sum\limits^{n}_{i=1}{X_{i}}$ is a Binomial distribution.

(b) The sampling distribution of the sample mean will be approximately normal.

Step-by-step explanation:

It is provided that random variables $X_{i}$ are independent and identically distributed Bernoulli random variables with p = 0.50.

The random sample selected is of size, n = 100.

(a)

Theorem:

Let $X_{1},\ X_{2},\ X_{3},...\ X_{n}$ be independent Bernoulli random variables, each with parameter p, then the sum of of thee random variables, $X=X_{1}+X_{2}+X_{3}...+X_{n}$ is a Binomial random variable with parameter n and p.

Thus, the distribution of $X=\sum\limits^{n}_{i=1}{X_{i}}$ is a Binomial distribution.

(b)

According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

The sample size is large, i.e. n = 100 > 30.

So, the sampling distribution of the sample mean will be approximately normal.

The mean of the distribution of sample mean is given by,

$\mu_{\bar x}=\mu=p=0.50$

And the standard deviation of the distribution of sample mean is given by,

$\sigma_{\bar x}=\sqrt{\frac{\sigma^{2}}{n}}=\sqrt{\frac{p(1-p)}{n}}=0.05$

(c)

Compute the value of $P(\bar X>0.50)$ as follows:

$P(\bar X>0.50)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{0.50-0.50}{0.05})\\$

$=P(Z>0)\\=1-P(Z$

*Use a z-table.

Thus, the value of $P(\bar X>0.50)$ is 0.50.

8 0

3 years ago

If y=5x - 3 find the value of y when X = 0

madreJ [45]

Since we know y=5x - 3 and we know that x=0 then its a matter of plugging in what we know and simplifying. y=5 x 0 - 3 we need to remember the order of operations for this problem. PEMDAS parenthesis exponent multiply divide add subtrac. Since 5 time 0 is multiplication and multiplication comes before subtracting in the oder of operations we will solve that first. 5 times 0 equals 0 since anything times 0 is 0. All that's left is to subtract 3 which gives us y=-3

8 0

3 years ago

Enter an equation in point-slope form for the line.

NISA [10]

Answer:

y + 1 = 3(x + 8)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = 3 and (a, b) = (- 8, - 1) , thus

y - (- 1) = 3(x - (- 8)), that is