Answer:
50.2 in^2
Step-by-step explanation:
Using the Formula
A=πr2
d=2r
Solving for A
A= 1/4 π d^2 = 1/4*π*8^2 = 50.26548
=50.2in^2
Answer:
Population of mosquitoes in the area at any time t is:

Step-by-step explanation:
assume population at any time t = P(t)
population increases at a rate proportional to the current population:
⇒dP/dt ∝ P
----(1)
where k is constant rate at which population is doubled
solving (1)

---- (2)
initial population = 400,000
population is doubled every week
⇒P(1)=2P(0)
Using (2)


In presence of predators amount is decreased by 50,000 per day
Then amount decreased per week = 350,000
In this case (1) becomes
---(3)
solving (3) by calculating integrating factor

Multiplying I.F with all terms of (3)

Integrating w.r.to t




at t=0



So, population of mosquitoes in the area at any time t is

<span>If so, 87 - 66 = 21 / (12-5) = 3 degrees Fahrenheit per hour.</span>
Hello human
Answer:
532.19 per week
Explanation:
You divide 27750 by 52.143 Because there are 52.143 weeks per year.
Thank you and gn ❤️✌
Answer:
hope it helps you see the attachment for further information