Answer:
Question 1. (2.2, -1.4)
Question 2. (1.33, 1)
Step-by-step explanation:
Equations for the given lines are
-----(1)
It is given that this line passes through two points (0, 2.5) and (2.2, 1.4).
------(2)
This equation passes through (0, -3) and (2.2, -1.4).
Now we have to find a common point through which these lines pass or solution of these equations.
From equations (1) and (2),
x =
x = 2.2
From equation (2),
y = -1.4
Therefore, solution of these equations is (2.2, -1.4).
Question 2.
The given equations are y = 1.5x - 1 and y = 1
From these equations,
1 = 1.5x - 1
1.5x = 2
x =
Therefore, the solution of the system of linear equations is (1.33, 1).
Answer:
coordinates are 6, -3
Step-by-step explanation:
When it's plotted out onto a graph, the answer comes down to 6, -3 (also remember, it's X then Y)
A) I included a graph, look below.
B)
Input the y in x = y + 3.
x = (-4x - 3) + 3
x = -4x + 0
Add 4x to both sides.
5x = 0
Divide both sides by 5.
x = 0
Input that x value in y = -4x - 3
y = -4(0) - 3
y = 0 - 3
y = -3
(0, -3)
C)
Convert both equations to Standard Form.
x = y + 3
Subtract y from both sides.
x - y = 3
y = -4x - 3
Add 4x to both sides.
4x + y = -3
Add the equations together.
4x + y = -3
x - y = 3
equals
5x = 0
Divide both sides by 5.
x = 0
Input that into one of the original equations.
0 = y + 3
Subtract 3 from both sides.
-3 = y
(0, -3)
Answer:
Step-by-step explanation:
The directrix is a vertical line, so the parabola is horizontal. The focus lies to the left of the directrix, so the parabola opens to the left.
For a left-opening parabola:
x = a(y-k)²+h,
a < 0,
vertex (h,k)
focal length p = 1/|4a|
focus (h-p, k)
directrix: x=h+p
Apply your data
focus (1,-4)
directrix x=2
vertex (1.5,-4).
focal length p = 0.5
a = -1/|4p| = -½
x = -½(y-2)²+ ½