Write an expression equal to 9^4

Mathematics

1 answer:

ale4655 [162]3 years ago

6 0

Answer:

9 x 9 x 9 x 9

Step-by-step explanation:

9^4 is a shorter and similar way of writing 9 x 9 x 9 x 9

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84 = 4(1– 49)<br><br> please give an explanation

aalyn [17]

Answer:

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2 years ago

Right in equation in slope intercept form that passes through (2 -6) and has a Y intercept located at (0,-7)

Lemur [1.5K]

Answer:

y=1/2x-7

Step-by-step explanation:

Trying solving for the slope before doing anything else. The equation to solve for the slope is:

$m=\frac{y_{2}-y_{1} }{x_2-x_1}$

Plug in your x and y values. For our purposes, 2 is x2, -6 is y2, 0 is x1 and -7 is y1. Put these values in and solve.

$m=\frac{-6-(-7)}{2-0}$

$m=\frac{-6+7}{2-0} \\
m=\frac{1}{2}$

The slope should come out to be 1/2, and now that we have our slope, we just plug in the values.

Slope intercept form: y=slope(x)+y intercept

y=1/2x-7

That should be the answer.

3 0

2 years ago

evaluate the expressions -8x+5-2x-4+5 when x=2 before and after simplifying. wich method do you prefer explain?

trasher [3.6K]

If x=2

Before :
-8(2)+5-2(2)-4+5
-16+5-4-4+5
-11-4+5
-14

After :
-10(2)+6
-20+6
-14
Simplify :
-8x+5-2x-4+5
-8x-2x+5-4+5
-10x+6

6 0

3 years ago

Rationalize the denominator of square root of negative 16 over open parentheses 1 plus i close parentheses plus open parentheses

emmasim [6.3K]

$\bf \cfrac{\sqrt{-16}}{(1+i)+(6+3i)}\implies \cfrac{\sqrt{-1\cdot 16}}{1+i+6+3i}\implies \cfrac{\sqrt{-1}\cdot \sqrt{16}}{7+4i}
\\\\\\
\cfrac{i\cdot \sqrt{4^2}}{7+4i}\implies \cfrac{4i}{7+4i}\impliedby 
\begin{array}{llll}
\textit{now, we'll multiply by the}\\
\textit{conjugate of the denominator}
\end{array}\\\\
-------------------------------\\\\$

$\bf \textit{and recall }\textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
\textit{also recall that }i^2=-1
\\\\
-------------------------------\\\\$

$\bf \cfrac{4i}{7+4i}\cdot \cfrac{7-4i}{7-4i}\implies \cfrac{4i(7-4i)}{(7+4i)(7-4i)}\implies \cfrac{28i-16i^2}{7^2-(4i)^2}
\\\\\\
\cfrac{28i-16(-1)}{49-(4^2i^2)}\implies \cfrac{28i+16}{49-[16(-1)]}\implies \cfrac{16+28i}{49+16}\implies \cfrac{16+28i}{65}
\\\\\\
\cfrac{16}{65}+\cfrac{28i}{65}$

5 0

4 years ago

Help me out here please! Thanks.

leva [86]

Answer:

A. $\frac{1}{5} log_{3}x +log_{3}y$