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2 years ago

-6t-7=17 what does t equal

Mathematics

1 answer:

Grace [21]2 years ago

7 0

Answer:

t=-4

Step-by-step explanation:

I know you don't care about any explanation, and just want the answer, but to get this, you can add 7 to both sides. Then you get -6t=24. Divide both sides by -6 and you get -4

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What does it mean when there is an open circle on a graph?

VladimirAG [237]

It means that the value will not be included. So if the open circle coincides with 2 on the x-axis then your limit will have x<2, which also means that the function is not continuous.

7 0

2 years ago

The table shows information about the masses of some dogs. a) Work out the minimum number of dogs that could have a mass of more

V125BC [204]

Information regarding various dogs' masses is displayed in the table.

(a) 4 bare minimum number of dogs that could weigh more than 27 kg.

(b) 17 dogs, in total, may weigh more than 27 kg.

Given that,

Information regarding various dogs' masses is displayed in the table.

(a)Calculate the bare minimum number of dogs that could weigh more than 27 kg.

(b)Calculate how many dogs, in total, may weigh more than 27 kg.

(a) 4 bare minimum of dogs that could weigh more than 27 kg.

Because the minimum number so lets assume that all dogs in 20≤x<30 are less then 27.

Therefore, 4 bare minimum of dogs that could weigh more than 27 kg.

(b) 17 dogs, in total, may weigh more than 27 kg.

Because the maximum number so lets assume that all dogs in 20≤x<30 are more then 27.

4+13=17

Therefore,17 dogs, in total, may weigh more than 27 kg.

To learn more about numbers visit: brainly.com/question/17429689

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6 0

11 months ago

Find the sample size necessary in order to be 95% confident when determining the true mean weight within 2 units (EC2). Assume t

bogdanovich [222]

Answer:

Step-by-step explanation:

Given:

Margin of error (E) = 2

Sample variance $(s^{2})$ = 44

Confidence level = 95%

The z- value at 95% confidence level is 1.96.

The sample using the provided information can be calculated as:

$n=(\frac{z(s)}{E})^{2} \\n=\frac{z^{2} s^{2} }{E^{2} } \\n=\frac{1.96^{2} (44) }{2^{2} }\\n= 42.52\\n=43$

Hence, the correct option is (c) 43.

8 0

3 years ago

Solve for x. -3/5x+1/5>7/20

kakasveta [241]

Answer:

Step-by-step explanation:

15 + 720 is 1120

3 0

2 years ago

Suppose that 20% of the employees of a given corporation engage in physical exercise activities during the lunch hour. Moreover,

Harlamova29_29 [7]

Answer:

a) 0.152 = 15.2% probability that this person is a female who engages in physical exercise activities during the lunch hour.

b) 0.248 = 24.8% probability that this person is a female who does not engage in physical exercise activities during the lunch hour.

Step-by-step explanation:

Question a:

20% of employees engage in physical exercise.

This 20% is composed by:

8% of 60%(males)

x% of 100 - 60 = 40%(females).

Then, x is given by:

$0.08*0.6 + 0.4x = 0.2$

$0.4x = 0.2 - 0.08*0.6$

$x = \frac{0.2 - 0.08*0.6}{0.4}$

$x = 0.38$

0.38 = 38%

Probability of being a female who engages in exercise:

40% are female, 38% of 40% engage in exercise. So

0.38*0.4 = 0.152

0.152 = 15.2% probability that this person is a female who engages in physical exercise activities during the lunch hour.

B. If we choose an employee at random from this corporation,what is the probability that this person is a female who does not engage in physical exercise activities during the lunch hour?

40% are female, 100% - 38% = 62% of 40% do not engage in exercise. So

0.62*0.4 = 0.248

0.248 = 24.8% probability that this person is a female who does not engage in physical exercise activities during the lunch hour.

3 0

2 years ago