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slega [8]
3 years ago
7

A student is studying the ways that different elements are similar to one another. Diagrams of atoms from four different element

s are shown above. Which two atoms are of elements in the same group of the periodic table?

Physics
1 answer:
RSB [31]3 years ago
7 0

Answer:

Atom 1 and Atom 4

Explanation:

On each group, the number of atoms on the outer shell is always the same as the number of the group. In atom 1 and Atom 4 there is 4 electrons on the outer shell, meaning that they are both in group 4.

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What was the hiker's total displacement?<br>A.24 km  B.4 km north  C.14 km northeast  D.0 km
kipiarov [429]
We can see it as two movements: one on the north-south axis and one on the west-east axis.

On the north-south Axis, the hiker went 8 km north and 4 km south, so in total the hiker went 4 km north (we can subtract one for the other and the direction remains that which was bigger)

On the west-easth Axis, the hiker went 6 km east and 6 km west, so in total the hiker  didn't move on this axis! or, he/she moved but then "came back"

So in total, the hiker only moved4 km north - answer B.

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7 0
3 years ago
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PLEASE HELP HURRY!!
kenny6666 [7]

You don't need both. GPE is the gravitational potential energy caused by the fact that an object is not touching the ground of the earth. KE is caused by an object moving. This problem says that the bowling ball "sits" meaning that you only need the GPE because it's not moving and it is not touching the surface. You would use the GPE equation to find how much Potential energy an object has. If you want its velocity,  you would set the answer to the GPE equation equal to the KE equation to find its velocity.

8 0
4 years ago
A plane travels down a runway 2750 m before it lifts off at an angle of 37 degrees from the horizontal. The plane has traveled 1
ss7ja [257]

Answer: 4.236km

Explanation:

Let's define the point (x, y) as:

x = horizontal distance moved.

y = vertical distance moved.

If the plane starts in the point (0, 0) then:

"A plane travels down a runway 2750 m before it lifts off..."

At this time, the position will be:

P = (0 + 2750m, 0) = (2750m, 0).

"it lifts off at an angle of 37 degrees from the horizontal. The plane has traveled 1.8 km since its wheels left the ground."

In this case, as the angle is measured from the horizontal, the components will be:

x = 1.8km*cos(37°) = 1.438km

y = 1.8km*sin(37°) =  1.083 km

Then the new position is:

P = (2750m + 1.438 km, 0 + 1.083 km)

Let's write it using the same units for all the quantities:

we know that

1km = 1000m

Then:

2750m = (2750/1000) km = 2.750 km.

Then we can write the new position as:

P = (2.750 km + 1.438km, 1.083km) = (4.188km, 1.083km)

Now, we define the displacement as the distance between the final position and the initial position.

The distance between two points (a, b) and (c, d) is:

D = √( (a  c)^2 + (b - d)^2)

In this case the points are:

(0, 0) for the initial position

(4.188km, 1.083km) for the final position.

And the displacement will be:

D = √( (4.188km - 0)^2 + (1.083 - 0)^2) = 4.236km

5 0
3 years ago
At some instant and location, the electric field associated with an electromagnetic wave in vacuum has the strength 70.5 V/m. Fi
jonny [76]

Answer:

The magnetic field strength, the energy density, and the power flow per unit area are 2.35\times10^{-7}\ T, 4.396\times10^{-8}\ J/m^3 and 13.18 W/m².

Explanation:

Given that,

Electromagnetic wave strength E= 70.5 V/m

(I). We need to calculate the magnetic field strength

Using formula of Electromagnetic wave strength

c= \dfrca{E}{B}

B=\dfrac{E}{c}

B=\dfrac{70.5 }{3\times10^{8}}

B=2.35\times10^{-7}\ T

(II). We need to calculate the energy density

Using formula of energy density

\mu_{total}=\mu_{E}+\mu_{B}

\mu_{total}=\dfrac{1}{2}\epsilon_{0}E^2+\dfrac{1}{2}\dfrac{B^2}{\mu_{0}}

\mu_{total}=\dfrac{1}{2}\times8.85\times10^{-12}\times(70.5)^2+\dfrac{1}{2}\times\dfrac{(2.35\times10^{-7})^2}{4\pi\times10^{-7}}

\mu_{total}=4.396\times10^{-8}\ J/m^3

(III). We need to calculate the power flow per unit area

Using formula of poynting vector

S=\dfrac{1}{\mu_{0}}EB

Put the value into the formula

S=\dfrac{1}{4\pi\times10^{-7}}\times70.5\times2.35\times10^{-7}

S=13.18\ W/m^2

Hence, The magnetic field strength, the energy density, and the power flow per unit area are 2.35\times10^{-7}\ T, 4.396\times10^{-8}\ J/m^3 and 13.18 W/m².

5 0
3 years ago
Which sector is not part of the circular flow model of the economy ?
morpeh [17]

Answer:

a. government sector

Explanation:

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3 years ago
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