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Annette [7]
3 years ago
14

plz help me with hw A bus of mass 1000 kg moving with a speed of 90km/hr stops after 6 sec by applying brakes then calculate the

distance travelled and amount of force applied.​
Physics
1 answer:
Lelechka [254]3 years ago
5 0

Answer:

Mass, M = 1000 kg

Speed, v = 90 km/h = 25 m/s

time, t = 6 sec.

Distance:

{ \tt{distance =  speed \times time }} \\ { \tt{distance = 25 \times 6}} \\ { \tt{distance = 150 \: m}}

Force:

{ \tt{force = mass \times acceleration}} \\ { \bf{but \: for \: acceleration : }} \\ from \: second \: equation \: of \: motion :  \\ { \bf{s = ut +  \frac{1}{2}  {at}^{2} }} \\  \\ { \tt{150 = (0 \times 6) + ( \frac{1}{2} \times a \times  {6}^{2} ) }} \\  \\ { \tt{acceleration = 8.33 \:  {ms}^{ - 2} }} \\  \\ { \tt{force = 1000 \times 8.33}} \\ { \tt{force = 8333.3 \: newtons}}

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Answer:

c. Tape measure.

Explanation:

Here in this case we have to measure the length of the object ( distance) so we need to use tape measure.

Tape measure is a device used to measure small distances. It consists of ribbon of clothes, plastic , fiber.  glass or metal strip with linear measurement markings. rest all options do not measure length.

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Q11:A police car in hot pursuit goes speeding past you. While the siren is approaching, the frequency of the sound you hear is 5
natulia [17]

Answer:

   v_s = 34.269 m / s

Explanation:

This is a Doppler effect exercise, in this case the observer is fixed and the sound source is moving.

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where the negative sign is used for when the source approaches the observer and the positive sign for when the source moves away from the observer

In this case when f ’= 5500 Hz approaches and when f’ = 4500 Hz moves away, let's write the two expressions together

          5500 = f (\frac{v}{v - v_s })

          4500 = f ( \frac{v}{v + vs})

let's solve these two equations

           \frac{5500}{4500}     = \frac{v+v_s}{v-v_s}

           1.222 (v-v_s) = v + v_s

            v_s (1+ 1.22) = v (1.222 -1)

            v_s = v   \frac{0.222}{2.223}

the speed of sound in air is v = 343 m / s

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When solar flares increase solar wind from the corona what do they cause in earth's upper atmosphere?
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4 years ago
Two wires A and B with circular cross-section are made of the same metal and have equal lengths, but the resistance of wire A is
Nesterboy [21]

Answer:

r₁/r₂ = 1/2 = 0.5

Explanation:

The resistance of a wire is given by the following formula:

R = ρL/A

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R = Resistance of wire

ρ = resistivity of the material of wire

L = Length of wire

A = Cross-sectional area of wire = πr²

r = radius of wire

Therefore,

R = ρL/πr²

<u>FOR WIRE A</u>:

R₁ = ρ₁L₁/πr₁²   -------- equation 1

<u>FOR WIRE B</u>:

R₂ = ρ₂L₂/πr₂²   -------- equation 2

It is given that resistance of wire A is four times greater than the resistance of wire B.

R₁ = 4 R₂

using values from equation 1 and equation 2:

ρ₁L₁/πr₁² = 4ρ₂L₂/πr₂²

since, the material and length of both wires are same.

ρ₁ = ρ₂ = ρ

L₁ = L₂ = L

Therefore,

ρL/πr₁² = 4ρL/πr₂²

1/r₁² = 4/r₂²

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taking square root on both sides:

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6 0
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Amiraneli [1.4K]

The diameter of the hose is 6.34 cm.

<em>"Your question is not complete, it seems to be missing the following information";</em>

the flow rate of water in the pipe is 0.012 m³/s

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Volumetric flow rate is directly proportional to the product of the area of the hose through which the water flows and the velocity of the water flowing through the hose.

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where;

<em>Q is the volumetric flow rate</em>

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<em>v is the velocity of flow</em>

The area of the hose is calculated as follow;

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The diameter of the hose is calculated as follows;

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Thus, the diameter of the hose is 6.34 cm.

Learn more here: brainly.com/question/15061170

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