Answer:
c. Tape measure.
Explanation:
Here in this case we have to measure the length of the object ( distance) so we need to use tape measure.
Tape measure is a device used to measure small distances. It consists of ribbon of clothes, plastic , fiber. glass or metal strip with linear measurement markings. rest all options do not measure length.
Answer:
v_s = 34.269 m / s
Explanation:
This is a Doppler effect exercise, in this case the observer is fixed and the sound source is moving.
f ’= f
where the negative sign is used for when the source approaches the observer and the positive sign for when the source moves away from the observer
In this case when f ’= 5500 Hz approaches and when f’ = 4500 Hz moves away, let's write the two expressions together
5500 = f (
)
4500 = f (
)
let's solve these two equations
1.222 (v-v_s) = v + v_s
v_s (1+ 1.22) = v (1.222 -1)
v_s = v
the speed of sound in air is v = 343 m / s
v_s = 343 0.09990
v_s = 34.269 m / s
They cause magnetic storms. A magnetic storm is a fleeting
disturbance of the Earth's magnetosphere. A magnetic storm is caused by a solar
wind shock wave associated with solar coronal mass ejections, coronal holes, or
solar flares. It typically strikes the Earth's magnetic field 24 to
36 hours after the event.
Answer:
r₁/r₂ = 1/2 = 0.5
Explanation:
The resistance of a wire is given by the following formula:
R = ρL/A
where,
R = Resistance of wire
ρ = resistivity of the material of wire
L = Length of wire
A = Cross-sectional area of wire = πr²
r = radius of wire
Therefore,
R = ρL/πr²
<u>FOR WIRE A</u>:
R₁ = ρ₁L₁/πr₁² -------- equation 1
<u>FOR WIRE B</u>:
R₂ = ρ₂L₂/πr₂² -------- equation 2
It is given that resistance of wire A is four times greater than the resistance of wire B.
R₁ = 4 R₂
using values from equation 1 and equation 2:
ρ₁L₁/πr₁² = 4ρ₂L₂/πr₂²
since, the material and length of both wires are same.
ρ₁ = ρ₂ = ρ
L₁ = L₂ = L
Therefore,
ρL/πr₁² = 4ρL/πr₂²
1/r₁² = 4/r₂²
r₁²/r₂² = 1/4
taking square root on both sides:
<u>r₁/r₂ = 1/2 = 0.5</u>
The diameter of the hose is 6.34 cm.
<em>"Your question is not complete, it seems to be missing the following information";</em>
the flow rate of water in the pipe is 0.012 m³/s
The given parameters;
- velocity of water in the hose, v = 3.8 m/s
- flow rate of water in the hose, Q = 0.012 m³/s
Volumetric flow rate is directly proportional to the product of the area of the hose through which the water flows and the velocity of the water flowing through the hose.
Q = Av
where;
<em>Q is the volumetric flow rate</em>
<em>A is the area of the hose</em>
<em>v is the velocity of flow</em>
The area of the hose is calculated as follow;

The diameter of the hose is calculated as follows;

Thus, the diameter of the hose is 6.34 cm.
Learn more here: brainly.com/question/15061170