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Annette [7]
3 years ago
14

plz help me with hw A bus of mass 1000 kg moving with a speed of 90km/hr stops after 6 sec by applying brakes then calculate the

distance travelled and amount of force applied.​
Physics
1 answer:
Lelechka [254]3 years ago
5 0

Answer:

Mass, M = 1000 kg

Speed, v = 90 km/h = 25 m/s

time, t = 6 sec.

Distance:

{ \tt{distance =  speed \times time }} \\ { \tt{distance = 25 \times 6}} \\ { \tt{distance = 150 \: m}}

Force:

{ \tt{force = mass \times acceleration}} \\ { \bf{but \: for \: acceleration : }} \\ from \: second \: equation \: of \: motion :  \\ { \bf{s = ut +  \frac{1}{2}  {at}^{2} }} \\  \\ { \tt{150 = (0 \times 6) + ( \frac{1}{2} \times a \times  {6}^{2} ) }} \\  \\ { \tt{acceleration = 8.33 \:  {ms}^{ - 2} }} \\  \\ { \tt{force = 1000 \times 8.33}} \\ { \tt{force = 8333.3 \: newtons}}

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Sum up the moments of the right and the left support:
∑ M2 = 0
F1 · 3.92 m = 46 kg · 9,81 m/s² · 4.46 m + 250 kg · 9.81 m/s² · 1.96 m
F 1 · 3.92 = 2012.6 + 4806.9
F 1 = 6819.5 : 3.92
F 1 = 1739.67 N
∑ M 1 = 0
F 2 · 3.92 m + 46 kg · 9.81 m/s² · 0.54 m = 250 kg · 9.81 m/s² · 1.96 m
F 2 · 3.92 + 243.68 = 4806.9
F 2 · 3.92 = 4563.22
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3 years ago
A bicyclist steadily speeds up from rest to 9.00m/s during a 7.20s time interval. Determine all unknowns and answer the followin
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Answer:

First, let us make some simplifications in notation. Taking the initial time to be zero, as if time is measured with a stopwatch, is a great simplification. Since elapsed time is

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A loaded ore car has a mass of 950 kg and rolls on rails with negligible friction. It starts from rest and is pulled up a mine s
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Answer:

a). P=11.04kW

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The power of the motor when the speed is constant is the work in a determinate time.

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The maximum power must the motor provide, is the maximum force with the maximum speed of the motor in this case

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