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il63 [147K]
2 years ago
14

A plane travels down a runway 2750 m before it lifts off at an angle of 37 degrees from the horizontal. The plane has traveled 1

.8 km since its wheels left the ground. What is the displacement of the plane?
Physics
1 answer:
ss7ja [257]2 years ago
5 0

Answer: 4.236km

Explanation:

Let's define the point (x, y) as:

x = horizontal distance moved.

y = vertical distance moved.

If the plane starts in the point (0, 0) then:

"A plane travels down a runway 2750 m before it lifts off..."

At this time, the position will be:

P = (0 + 2750m, 0) = (2750m, 0).

"it lifts off at an angle of 37 degrees from the horizontal. The plane has traveled 1.8 km since its wheels left the ground."

In this case, as the angle is measured from the horizontal, the components will be:

x = 1.8km*cos(37°) = 1.438km

y = 1.8km*sin(37°) =  1.083 km

Then the new position is:

P = (2750m + 1.438 km, 0 + 1.083 km)

Let's write it using the same units for all the quantities:

we know that

1km = 1000m

Then:

2750m = (2750/1000) km = 2.750 km.

Then we can write the new position as:

P = (2.750 km + 1.438km, 1.083km) = (4.188km, 1.083km)

Now, we define the displacement as the distance between the final position and the initial position.

The distance between two points (a, b) and (c, d) is:

D = √( (a  c)^2 + (b - d)^2)

In this case the points are:

(0, 0) for the initial position

(4.188km, 1.083km) for the final position.

And the displacement will be:

D = √( (4.188km - 0)^2 + (1.083 - 0)^2) = 4.236km

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Answer:

Option B is correct.

Explanation:

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3 years ago
The arrows on the diagram show the ocean floor spreading from the Redge what three kinds of evidence scientists have found suppo
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3 years ago
Now imagine a person dragging a 50 kg box along the ground with a rope, as
ANTONII [103]

Answer:

The coefficient of static friction between the box and floor is, μ = 0.061

Explanation:

Given data,

The mass of the box, m = 50 kg

The force exerted by the person, F = 50 N

The time period of motion, t = 10 s

The frictional force acting on the box, f = 30 N

The normal force on the box, η = mg

                                                     = 50 x 9.8

                                                     = 490 N

The coefficient of friction,

                            μ = f/ η

                               = 30 / 490

                               = 0.061

Hence, the coefficient of static friction between the box and floor is, μ = 0.061

7 0
3 years ago
Can someone explain this
Alborosie

Answer:

gravity

Explanation:

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8 0
3 years ago
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In the future, a spaceship has traveled three percent of the distance to a space station. If the ship has traveled 2.9 x 10^7 mi
leva [86]

Answer:

9.38 * 10^8 miles

Explanation:

The spaceship has traveled 3% of the distance to a space station and it has traveled 2.9 * 10^7 miles.

Let the total distance from the ship's starting point to the space station be x.

This means that:

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The total distance to be traveled is 9.67 * 10^8 miles.

Therefore, the distance left to travel is:

9.67 * 10^8 - 2.9 * 19^7\\\\= 9.38 * 10^8 miles

6 0
3 years ago
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