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Anon25 [30]
3 years ago
7

A softball with a mass of 0.11 kg goes moves at a speed of 12 m/s, then the ball is hit by a bat and rebounds in the opposite di

rection at a speed of 15 m/s. What is the change in momentum of the ball?
Physics
1 answer:
dimulka [17.4K]3 years ago
7 0
=1244 and that's from my math book
You might be interested in
A motorcycle has a mass of 2.50×10^2. A constant force is exerted on it for 60.0s. The motorcycles initial velocity is 6.00 m/s
Margarita [4]

The change in momentum is 5500 kg m/s

Explanation:

The change in momentum of an object is given by

\Delta p = m(v-u)

where

m is the mass of the object

v is the final velocity

u is the initial velocity

In this problem, we have:

m=2.50\cdot 10^2 kg (mass of the motorcycle)

v=28.0 m/s (final velocity)

u=6.0 m/s (initial velocity)

Therefore, the change in momentum is

\Delta p=(2.50\cdot 10^2)(28.0-6.0)=5500 kg m/s

Learn more about change in momentum:

brainly.com/question/9484203

#LearnwithBrainly

8 0
3 years ago
Which of the following is an example of a conductor?
nordsb [41]
Answer: B. a gold chain
7 0
3 years ago
Which of the following would be the best insulator? air aluminum copper silver
77julia77 [94]

Answer:

aluminum will be the best insulator...coz it have a high resistance

4 0
3 years ago
Which example best represents translational kenetic energy
Mila [183]

Answer:

an apple falling off a tree

Explanation:

5 0
3 years ago
PLEASE HELP!! At what temperature will silver have a resistivity that is four times the resistivity of tungsten at room temperat
Svetach [21]
Consider 20 deg.C. as room temperature.

From tables,
Silver has a resistivity of  1.6*10^-8 ohm-m at 20 deg.C, and it increases by 0.0038 ohm-m per deg.K increase.
Therefore if the temperature rise above 20 deg.C is T, then silver will have resistivity of
1.6*10^-8(1 + 0.0038T) ohm-m

At room temperature, the resistivity of tungsten (from tables) is 5.6*10^-8.

The resistivity of silver will be 4 times that of tungsten (at room temperature) when
1.6*10^-8(1 + 0.0038T) = 4*5.6*10^-8
1 + 0.0038T = 14
T = 13/.0038 = 3421 deg.K approx

Answer: 20 + 3421 = 3441 °C
4 0
3 years ago
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